JS实现浏览上传文件的代码
程序员文章站
2022-09-08 20:25:54
废话不多说了，直接给大家贴代码了，具体代码如下所示：
...
废话不多说了，直接给大家贴代码了，具体代码如下所示：
<div style="position:relative;width:380px;">
<iframe id="t_load" name="t_load" style="display: none"></iframe>
<form action="" method="post" enctype="multipart/form-data" name="form1" target="t_load">
<input type='text' name='textfield' id='textfield' style="height:22px; border:2px solid #cdcdcd; width:230px; border-radius:50px;" />
<input type='button' value='浏览...' style="display: inline-block;
margin-bottom: 0;
font-size: 14px;
border-radius: 4px;
padding: 6px 12px;
margin: 2px 2px;
border: 1px solid #357ebd;
background: #1b9ad5;
color: #fff;" />
<input type="file" name="file1" accept="image/jpeg, image/gif" id="file1" onchange="document.getelementbyid('textfield').value=this.value" style="position:absolute; top:5px; right:74px; height:27px; filter:alpha(opacity:0);opacity: 0;width:300px" />
<input type="button" name="button" onclick="mysubmit()" value="上传" style="display: inline-block;
margin-bottom: 0;
font-size: 14px;
border-radius: 4px;
padding: 6px 12px;
margin: 2px 2px;
border: 1px solid #357ebd;
background: #1b9ad5;
color: #fff;">
</form>
</div>
<div style="display:none;color:#6d6d72;font-size: 20px;" id="res"></div>
<script>
function mysubmit() {
var a = document.getelementbyid("textfield").value;
if(a == "") {
alert("请上传文件");
return;
}
document.form1.submit();
ajaxsend();
}
function ajaxsend() {
var xmlhttp;
if(window.activexobject) {
xmlhttp = new activexobject("msxml2.xmlhttp");
} else {
xmlhttp = new xmlhttprequest();
}
xmlhttp.open("post", "upload", true);
xmlhttp.onreadystatechange = function() {
xmlhttp.readystate;
if(xmlhttp.readystate == 4) {
res.innerhtml = "上传成功！";
settimeout(function() {
res.innerhtml = "";
}, 2000);
} else {
document.getelementbyid("res").style.display = "inline";
}
}
xmlhttp.send();
var obj = document.getelementbyid('textfield');
obj.outerhtml = obj.outerhtml;
}
</script>
总结
以上所述是小编给大家介绍的js实现浏览上传文件的代码，希望对大家有所帮助
上一篇： 这难道又是印度人干的？