mysql 查询当天、本周,本月,上一个月的数据

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

select * from 表名 where to_days( now( ) ) - to_days( 时间字段名) <= 1

近7天

select * from 表名 where date_sub(curdate(), interval 7 day) <= date(时间字段名)

近30天

select * from 表名 where date_sub(curdate(), interval 30 day) <= date(时间字段名)

本月

select * from 表名 where date_format( 时间字段名, '%y%m' ) = date_format( curdate( ) , '%y%m' )

上一月

select * from 表名 where period_diff( date_format( now( ) , '%y%m' ) , date_format( 时间字段名, '%y%m' ) ) =1

查询本季度数据

select * from `ht_invoice_information` where quarter(create_date)=quarter(now());

查询上季度数据

select * from `ht_invoice_information` where quarter(create_date)=quarter(date_sub(now(),interval 1 quarter));

查询本年数据

select * from `ht_invoice_information` where year(create_date)=year(now());

查询上年数据

select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据

select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now());

查询上周的数据

select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now())-1;

查询上个月的数据

select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(date_sub(curdate(), interval 1 month),'%y-%m')
select * from user where date_format(pudate,'%y%m') = date_format(curdate(),'%y%m') ; 
select * from user where weekofyear(from_unixtime(pudate,'%y-%m-%d')) = weekofyear(now()) 
select * from user where month(from_unixtime(pudate,'%y-%m-%d')) = month(now()) 
select * from user where year(from_unixtime(pudate,'%y-%m-%d')) = year(now()) and month(from_unixtime(pudate,'%y-%m-%d')) = month(now()) 
select * from user where pudate between 上月最后一天 and 下月第一天 

查询当前月份的数据

select name,submittime from enterprise  where date_format(submittime,'%y-%m')=date_format(now(),'%y-%m')

查询距离当前现在6个月的数据

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

ps:下面看下mysql如何查询当天信息？

原来不是太熟悉sql查询语句，什么都是用到了再去查去找，还好网络提供给我们很多支持。今天又用到了一个语句，一时间真想不出怎么解决，到网上看了看，感觉就有一个，怎么那么简单啊。需要积累的东西真是太多了。

今天就把我这个简单的问题记录下来吧!算是一个积累：

mysql查询当天的所有信息：

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

这个有一些繁琐，还有简单的写法：

select * from table where date(regdate) = curdate();

date()函数获取日期部分, 扔掉时间部分，然后与当前日期比较即可