压缩包密码破解示例分享(类似典破解)
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2022-08-14 09:08:35
昨天翻硬盘,找到一个好东西,可惜自己加了密码自己不记得了。试了几个常用的没试出来,于是写了这么个小脚本来替我尝试。。呵呵,还真给解出来了。python脚本内容如下,跑跑自己...
昨天翻硬盘,找到一个好东西,可惜自己加了密码自己不记得了。试了几个常用的没试出来,于是写了这么个小脚本来替我尝试。。呵呵,还真给解出来了。
python脚本内容如下,跑跑自己加密的压缩包还不错
复制代码 代码如下:
# -*- coding: utf-8 -*-
import sys,os
def iselementuniq(list):
"""
判断list中的元素是否为唯一的
"""
for word in list:
if list.count(word)>1:
return false
return true
def genpswlist():
"""
要求用户输入词,并根据单词组合密码,只尝试四个单词来组合,并限制密码长度为20。写的比较挫
"""
psw=raw_input('input a word>')
wordlist = []
while psw:
wordlist.append(psw)
psw=raw_input('input a word>')
print wordlist
global g_pswlist
g_pswlist = []
for word in wordlist:
g_pswlist.append(word)
for word1 in wordlist:
for word2 in wordlist:
locallist = [word1, word2]
if iselementuniq(locallist):
tmp = word1 + word2
if len(tmp) < 20:
g_pswlist.append(tmp)
for word1 in wordlist:
for word2 in wordlist:
for word3 in wordlist:
locallist = [word1, word2, word3]
if iselementuniq(locallist):
tmp = word1 + word2 + word3
if len(tmp) < 20:
g_pswlist.append(tmp)
for word1 in wordlist:
for word2 in wordlist:
for word3 in wordlist:
for word4 in wordlist:
locallist = [word1, word2, word3, word4]
if iselementuniq(locallist):
tmp = word1 + word2 + word3 + word4
if len(tmp) < 20:
g_pswlist.append(tmp)
print 'gen psw is:', g_pswlist
def testunzippack(filename):
"""
尝试用密码来解压压缩包
"""
command = ""
for psw in g_pswlist:
command = "7z e -p%s -y %s" %(psw,filename)
print command
ret = os.system(command)
if ret == 0:
print 'right psw is ', psw
break
def main(filename):
genpswlist()
testunzippack(filename)
if __name__ == '__main__':
if len(sys.argv) != 2:
print 'argv error'
print 'example:test_7z_psw.py 1.7z'
sys.exit(1)
main(sys.argv[1])