ACM日期计算(C++实现):输入一个日期,格式如:2010 10 24 ,判断这一天是这一年中的第几天
程序员文章站
2022-08-04 17:02:21
//#include "stdafx.h"
#include
using namespace std;
bool isleapyear(unsigned int...
//#include "stdafx.h" #include using namespace std; bool isleapyear(unsigned int year) { if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) { return true; } else { return false; } } int getdays(unsigned int year, unsigned int month, unsigned int day) { if (month == 0 || month > 12 || day == 0 || day > 31) { return -1; } int days = 0;//天数 switch (month - 1) {//累加本月之前的天数 case 11: days += 30; case 10: days += 31; case 9: days += 30; case 8: days += 31; case 7: days += 31; case 6: days += 30; case 5: days += 31; case 4: days += 30; case 3: days += 31; case 2: days += isleapyear(year) == true ? 29 : 28;//若是闰年则+ 29,否则+ 28 case 1: days += 31; } days += day;//加上本月天数 return days; } int main() { int n = 0; cin >> n; while (n--) { unsigned int year = 0; unsigned int month = 0; unsigned int day = 0; cin >> year >> month >> day; cout << getdays(year, month, day) << endl; } //system("pause"); return 0; }
上一篇: 程序开发面试题
下一篇: 前端使用自定义字体是一种什么样的体验