编程判断输入整数的正负性和奇偶性。 **输入格式要求:“%d“ 提示信息:“Input m:“ **输出格式要求: 如果是负偶数,则输出“%d is a negative even\n“ 如果是负奇
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2022-07-15 12:21:13
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编程判断输入整数的正负性和奇偶性。
**输入格式要求:"%d" 提示信息:“Input m:”
**输出格式要求:
如果是负偶数,则输出"%d is a negative even\n"
如果是负奇数,则输出"%d is a negative odd\n"
如果是正偶数,则输出"%d is a positive even\n"
如果是正奇数,则输出"%d is a positive odd\n"
如果是0,则输出"%d is zero. It is an even\n"
程序运行示例1:
Input m:6↙
6 is a positive even
程序运行示例2:
Input m:0↙
0 is zero. It is an even
#include<stdio.h>
int main()
{
int x;
printf("Input m:");
scanf("%d",&x);
if(x!=0)
{
if(x<0)
{
if(x%2==0)
{
printf("%d is a negative even\n",x);
}
if(x%2!=0)
{
printf("%d is a negative odd\n",x);
}
}
if(x>0)
{
if(x%2==0)
{
printf("%d is a positive even\n",x);
}
if(x%2!=0)
{
printf("%d is a positive odd\n",x);
}
}
}
else
{
printf("%d is zero. It is an even\n",x);
}
}