POJ 2210 Metric Time G++

#include <iostream>
#include <cstdio>
using namespace std;
int hs[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int he[13]={0,0,31,59,90,120,151,181,212,243,273,304,334};
int tian(int dy,int mh,int yr)//与 1.1.2000 相差几天
{
	int sum=dy-1;
	/*
	for(int i=1;i<mh;i++)
	{
		if(i==2 && ((yr%4==0 && yr%100!=0)||(yr%400==0)))//闰年 
		{
			sum=sum+29;
		}else
		{
			sum=sum+hs[i];
		}
	}*/
	sum=sum+he[mh];
	if(mh>2 && ((yr%4==0 && yr%100!=0)||(yr%400==0)))//闰年
	{
		sum=sum+1;
	}
	/*
	for(int i=2000;i<yr;i++)
	{
		if((i%4==0 && i%100!=0)||(i%400==0))//闰年 
		{
			sum=sum+366;
		}else
		{
			sum=sum+365;
		}		
	}*/
    if (yr !=2000)//抄博友 巧妙 
        sum =sum+ 366 + 365 * (yr - 1 - 2000) + (yr - 1 - 2000) /4- (yr -1 - 2000) / 100+ (yr -1-2000) / 400;	 
	return sum;
} 
int miao(int hr,int mn,int sc)
{
	return sc+mn*60+hr*60*60;
}
int main()
{
	/* 
	for(int i=2;i<13;i++)
	{
		he[i]=he[i-1]+hs[i-1];
		cout<<he[i]<<" ";
	}
	cout<<endl;*/
	int n;
	scanf("%d",&n);
	for(int i=0;i<n;i++)
	{
		int hr,mn,sc,dy,mh,yr;
		scanf("%d:%d:%d %d.%d.%d",&hr,&mn,&sc,&dy,&mh,&yr);
		int msec=miao(hr,mn,sc);
		int mday=tian(dy,mh,yr);
		//cout<<msec<<" "<<mday<<endl;
		msec=msec*(125.0/(108.0));
		//cout<<msec<<endl;
		printf("%d:%d:%d %d.%d.%d\n",(msec/10000)%10,(msec%10000)/100,msec%100,
		(mday%100)+1,((mday%1000)/100)+1,mday/1000);
	}
	return 0;
}