数字颠倒

#include <iostream>

using namespace std;

char t[32];

int main()
{
	int a,k = 0;
	cin>>a;
	while(a)
	{
		int temp = a % 10;
		t[k] = temp + '0';
		k++;
		a = a / 10;
	}
	cout<<t;

	return 0;
}