2020 CCPC Wannafly Winter Camp Day1 Div1&2(重现赛)B题解
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2022-07-12 15:06:42
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链接:https://ac.nowcoder.com/acm/contest/3979/B
来源:牛客网
B,签到题。按m->1倒序来依次还原字符串。
#include<bits/stdc++.h>
//#pragma GCC optimize(2)
#include<iostream>
#include<stdio.h>
#include<string>
#include<cstring>
#include<set>
#include<map>
#include<stack>
#include<queue>
#include<algorithm>
#define ll long long
using namespace std;
const ll N = 10000;
int n, m, chul[N][3];
string p[N];
int getnum(char c)
{
if (c >= 'A' && c <= 'Z')
return c - 'A' + 26;
return c - 'a';
}
char getst(int c)
{
if (c <= 25)
return char(c + 'a');
else
return char(c - 26 + 'A');
}
int main()
{
//ios::sync_with_stdio(false);
#ifndef ONLINE_JUDGE
freopen("182.txt", "r", stdin);
#endif // ONLINE_JUDGE
scanf("%d%d", &n, &m);
for (int i = 1; i <= m; i++)
{
scanf("%d%d", &chul[i][1], &chul[i][2]);
}
for (int i = 1; i <= n; i++)
{
cin >> p[i];
}
for (int i = m; i; i--)
{
int bcl = chul[i][2];//被处理的字符串编号
int cl = chul[i][1];//处理字符串;
string a = p[cl], b = p[bcl], c = "";//a是处理的,b是被处理的,c用来还原、
while (a.size() < b.size())//拓展a
a = a + a;
for (int i = 0; i < b.size(); i++)//开始还原,c[i]+a[i]%52=b[i]->>c[i]=b[i]+52-a[i]%52;
{
char t = (getst((getnum(b[i]) + 52 - getnum(a[i])) % 52));
c += t;
}
p[bcl] = c;
}
for (int i = 1; i <= n; i++)
cout << p[i] << endl;
return 0;
}