oracle 身份证校验函数的实例代码
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2022-07-06 10:58:08
1、正则表达式写法:
create or replace function func_checkidcard (p_idcard in varchar2) return in...
1、正则表达式写法:
create or replace function func_checkidcard (p_idcard in varchar2) return int is v_regstr varchar2 (2000); v_sum number; v_mod number; v_checkcode char (11) := '10x98765432'; v_checkbit char (1); v_areacode varchar2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,'; begin case lengthb (p_idcard) when 15 then -- 15位 if instrb (v_areacode, substr (p_idcard, 1, 2) || ',') = 0 then return 0; end if; if mod (to_number (substrb (p_idcard, 7, 2)) + 1900, 400) = 0 or ( mod (to_number (substrb (p_idcard, 7, 2)) + 1900, 100) <> 0 and mod (to_number (substrb (p_idcard, 7, 2)) + 1900, 4) = 0 ) then -- 闰年 v_regstr := '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$'; else v_regstr := '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$'; end if; if regexp_like (p_idcard, v_regstr) then return 1; else return 0; end if; when 18 then -- 18位 if instrb (v_areacode, substrb (p_idcard, 1, 2) || ',') = 0 then return 0; end if; if mod (to_number (substrb (p_idcard, 7, 4)), 400) = 0 or ( mod (to_number (substrb (p_idcard, 7, 4)), 100) <> 0 and mod (to_number (substrb (p_idcard, 7, 4)), 4) = 0 ) then -- 闰年 v_regstr := '^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9xx]$'; else v_regstr := '^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9xx]$'; end if; if regexp_like (p_idcard, v_regstr) then v_sum := ( to_number (substrb (p_idcard, 1, 1)) + to_number (substrb (p_idcard, 11, 1)) ) * 7 + ( to_number (substrb (p_idcard, 2, 1)) + to_number (substrb (p_idcard, 12, 1)) ) * 9 + ( to_number (substrb (p_idcard, 3, 1)) + to_number (substrb (p_idcard, 13, 1)) ) * 10 + ( to_number (substrb (p_idcard, 4, 1)) + to_number (substrb (p_idcard, 14, 1)) ) * 5 + ( to_number (substrb (p_idcard, 5, 1)) + to_number (substrb (p_idcard, 15, 1)) ) * 8 + ( to_number (substrb (p_idcard, 6, 1)) + to_number (substrb (p_idcard, 16, 1)) ) * 4 + ( to_number (substrb (p_idcard, 7, 1)) + to_number (substrb (p_idcard, 17, 1)) ) * 2 + to_number (substrb (p_idcard, 8, 1)) * 1 + to_number (substrb (p_idcard, 9, 1)) * 6 + to_number (substrb (p_idcard, 10, 1)) * 3; v_mod := mod (v_sum, 11); v_checkbit := substrb (v_checkcode, v_mod + 1, 1); if v_checkbit = upper(substrb(p_idcard,18,1)) then return 1; else return 0; end if; else return 0; end if; else return 0; -- 身份证号码位数不对 end case; exception when others then return 0; end fn_checkidcard; / show err;
2、非正则表达式写法
create or replace function func_checkidcard (p_idcard in varchar2) return number is v_sum number; v_mod number; v_length number; v_date varchar2(10); v_isdate boolean; v_isnumber boolean; v_isnumber_17 boolean; v_checkbit char (1); v_checkcode char (11) := '10x98765432'; v_areacode varchar2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,'; --[isnumber]-- function isnumber (p_string in varchar2) return boolean is i number; k number; flag boolean; v_length number; begin /* 算法: 通过ascii码判断是否数字,介于[48, 57]之间。 select ascii('0'),ascii('1'),ascii('2'),ascii('3'),ascii('4'),ascii('5'),ascii('6'),ascii('7'),ascii('8'),ascii('9') from dual; */ flag := true; select length(p_string) into v_length from dual; for i in 1..v_length loop k := ascii(substr(p_string,i,1)); if k < 48 or k > 57 then flag := false; exit; end if; end loop; return flag; end isnumber; --[isdate]-- function isdate (p_date in varchar2) return boolean is v_flag boolean; v_year number; v_month number; v_day number; v_isleapyear boolean; begin --[初始化]-- v_flag := true; --[获取信息]-- v_year := to_number(substr(p_date,1,4)); v_month := to_number(substr(p_date,5,2)); v_day := to_number(substr(p_date,7,2)); --[判断是否为闰年]-- if (mod(v_year,400) = 0) or (mod(v_year,100) <> 0 and mod(v_year,4) = 0) then v_isleapyear := true; else v_isleapyear := false; end if; --[判断月份]-- if v_month < 1 or v_month > 12 then v_flag := false; return v_flag; end if; --[判断日期]-- if v_month in (1,3,5,7,8,10,12) and (v_day < 1 or v_day > 31) then v_flag := false; end if; if v_month in (4,6,9,11) and (v_day < 1 or v_day > 30) then v_flag := false; end if; if v_month in (2) then if (v_isleapyear) then --[闰年]-- if (v_day < 1 or v_day > 29) then v_flag := false; end if; else --[非闰年]-- if (v_day < 1 or v_day > 28) then v_flag := false; end if; end if; end if; --[返回结果]-- return v_flag; end isdate; begin /* 返回值说明: -1 身份证号码位数不对 -2 身份证号码出生日期超出范围 -3 身份证号码含有非法字符 -4 身份证号码校验码错误 -5 身份证号码地区码非法 身份证号码通过校验 */ --[长度校验]-- if p_idcard is null then return -1; end if ; select lengthb(p_idcard) into v_length from dual; if v_length not in (15,18) then return -1; end if; --[区位码校验]-- if instrb(v_areacode, substr(p_idcard, 1, 2)||',') = 0 then return -5; end if; --[格式化校验]-- if v_length = 15 then v_isnumber := isnumber (p_idcard); if not (v_isnumber) then return -3; end if; elsif v_length = 18 then v_isnumber := isnumber (p_idcard); v_isnumber_17 := isnumber (substr(p_idcard,1,17)); if not ((v_isnumber) or (v_isnumber_17 and upper(substr(p_idcard,18,1)) = 'x')) then return -3; end if; end if; --[出生日期校验]-- if v_length = 15 then select '19'||substr(p_idcard,7,6) into v_date from dual; elsif v_length = 18 then select substr(p_idcard,7,8) into v_date from dual; end if; v_isdate := isdate (v_date); if not (v_isdate) then return -2; end if; --[校验码校验]-- if v_length = 18 then v_sum := ( to_number (substrb (p_idcard, 1, 1)) + to_number (substrb (p_idcard, 11, 1)) ) * 7 + ( to_number (substrb (p_idcard, 2, 1)) + to_number (substrb (p_idcard, 12, 1)) ) * 9 + ( to_number (substrb (p_idcard, 3, 1)) + to_number (substrb (p_idcard, 13, 1)) ) * 10 + ( to_number (substrb (p_idcard, 4, 1)) + to_number (substrb (p_idcard, 14, 1)) ) * 5 + ( to_number (substrb (p_idcard, 5, 1)) + to_number (substrb (p_idcard, 15, 1)) ) * 8 + ( to_number (substrb (p_idcard, 6, 1)) + to_number (substrb (p_idcard, 16, 1)) ) * 4 + ( to_number (substrb (p_idcard, 7, 1)) + to_number (substrb (p_idcard, 17, 1)) ) * 2 + to_number (substrb (p_idcard, 8, 1)) * 1 + to_number (substrb (p_idcard, 9, 1)) * 6 + to_number (substrb (p_idcard, 10, 1)) * 3; v_mod := mod (v_sum, 11); v_checkbit := substrb (v_checkcode, v_mod + 1, 1); if v_checkbit = upper(substrb(p_idcard,18,1)) then return 1; else return -4; end if; else return 1; end if; end func_checkidcard; / show err;
总结
以上所述是小编给大家介绍的oracle 身份证校验函数,希望对大家有所帮助
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