pycrypto实现AES加密和解密
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2022-07-04 09:08:28
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一 代码
# -*- coding: UTF-8 -*- import string import random from Crypto.Cipher import AES def keyGenerater(length): '''生成指定长度的秘钥''' if length not in (16, 24, 32): return None x = string.ascii_letters+string.digits return ''.join([random.choice(x) for i in range(length)]) def encryptor_decryptor(key, mode): return AES.new(key, mode, b'0000000000000000') #使用指定密钥和模式对给定信息进行加密 def AESencrypt(key, mode, text): encryptor = encryptor_decryptor(key, mode) return encryptor.encrypt(text) #使用指定密钥和模式对给定信息进行解密 def AESdecrypt(key, mode, text): decryptor = encryptor_decryptor(key, mode) return decryptor.decrypt(text) if __name__ == '__main__': text = 'Python3.5 is excellent.' key = keyGenerater(16) #随机选择AES的模式 mode = random.choice((AES.MODE_CBC, AES.MODE_CFB, AES.MODE_ECB, AES.MODE_OFB)) if not key: print('Something is wrong.') else: print('key:', key) print('mode:', mode) print('Before encryption:', text) #明文必须以字节串形式,且长度为16的倍数 text_encoded = text.encode() text_length = len(text_encoded) padding_length = 16 - text_length%16 text_encoded = text_encoded + b'0'*padding_length text_encrypted = AESencrypt(key, mode, text_encoded) print('After encryption:', text_encrypted) text_decrypted =AESdecrypt(key, mode, text_encrypted) print('After decryption:', text_decrypted.decode()[:-padding_length])
二 运行结果
E:\python\python可以这样学\第18章 密码学编程\code>python AES_test.py
('key:', 'D5pcO6iu0HIbj3I2')
('mode:', 1)
('Before encryption:', 'Python3.5 is excellent.')
('After encryption:', '\xf4\x15\x9f\xaf\xea\xd0\n\x03\xfdf\xf6}9\xaa\xa34\xb4\x1eL2\x0e \x16\xa5 \xff?\x8bA\x8e\xdd\xa8')
('After decryption:', u'Python3.5 is excellent.')