Python-八进制、二进制互转换
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2022-07-03 20:42:25
Python-八进制转二进制input_str = input('请输入待转八进制数:')list_num = []list_octal = []lists = []t = 0def octal_binary(): """用于八进制转二进制""" for i in input_str: list_num.append(i) # print(list_num) list_deal = [int(k) for k in list_num]...
Python-八进制转二进制
input_str = input('请输入待转八进制数:')
list_num = []
list_octal = []
lists = []
t = 0
def octal_binary():
"""用于八进制转二进制"""
for i in input_str:
list_num.append(i)
# print(list_num)
list_deal = [int(k) for k in list_num]
# print(list_deal)
list_num.clear()
for j in list_deal:
while True:
if j != 1:
n = str(j % 2)
list_octal.append(n)
j //= 2
elif j == 1:
list_octal.append('1')
list_octal.reverse()
if len(list_octal) % 3 == 0:
pass
elif len(list_octal) % 3 == 1:
list_octal.insert(0, '0')
list_octal.insert(1, '0')
elif len(list_octal) % 3 == 2:
list_octal.insert(0, '0')
lists.extend(list_octal)
list_octal.clear()
break
list_octal.reverse()
num_str = int(''.join(lists))
print("该八进制数转化为二进制数为:%d" % num_str)
Python-二进制转八进制
input_str = input('请输入待转二进制数:')
initial_list = []
once_deal_list = []
second_deal_list = []
l_int = len(input_str)
y = 0
r = 2
k = 0
def cut_str():
"""字符串切片"""
i = 0
while i < l_int:
once_deal_list.append(initial_list[i:(i + 3)])
i += 3
def repair_str():
"""不足3位进行补零"""
for t in input_str:
initial_list.append(int(t))
if input_str.isdecimal():
print('数字验证通过')
if l_int % 3 == 0:
cut_str()
elif l_int % 3 == 2:
initial_list.insert(0, 0)
cut_str()
else:
initial_list.insert(0, 0)
initial_list.insert(1, 0)
cut_str()
else:
print('验证失败请重新输入')
return
def octonary():
"""转换为八进制"""
repair_str()
global k
global r
for g in once_deal_list:
for j in g:
k += int(j) * 2 ** r
r -= 1
second_deal_list.append(k)
r = 2
k = 0
# print('转换成的八进制数为:', end='')
# for n in second_deal_list:
# print(n, end='')
# print
end_list = [str(h) for h in second_deal_list]
end_num = int(''.join(end_list))
print('转换成的八进制数为:%d' % end_num)
octonary()
本文地址:https://blog.csdn.net/YIGAOYU/article/details/110226748
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