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关于结果处理类型input的代码演示-深入Struts2

程序员文章站 2022-07-02 12:10:10
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一 Input因为年龄输入错误自动跳转回输入界面
1、struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd";>
<struts>
        <package name="default" namespace="/" extends="struts-default">
                <default-action-ref name="index"></default-action-ref>
                <action name="index">
                        <result>/error.jsp</result>
                </action>
                
                <action name="*_*_*" method="{2}" class="com.cakin.{3}.{1}Action">
                        <result>/result.jsp</result>
                        <result name="add">/{2}.jsp</result>
                        <result name="update">/{2}.jsp</result>
                </action>
                
                <action name="LoginAction" method="login" class="com.cakin.action.LoginAction">
                        <result>/success.jsp</result>
                        <result name="input">/login.jsp</result>
                </action>
        </package>
</struts>   
2、User.java
package com.cakin.po;
 
import java.util.List;
 
public class User {
        private String username;
        
        private String password;
        
        private int age;
        
        public int getAge() {
                return age;
        }
        public void setAge(int age) {
                this.age = age;
        }
        private List<User> booklist;
        
        public List<User> getBooklist() {
                return booklist;
        }
        public void setBooklist(List<User> booklist) {
                this.booklist = booklist;
        }
        public String getUsername() {
                return username;
        }
        public void setUsername(String username) {
                this.username = username;
        }
        public String getPassword() {
                return password;
        }
        public void setPassword(String password) {
                this.password = password;
        }
}
3、login.jsp
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
   
    <title>My JSP 'login.jsp' starting page</title>
   
        <meta http-equiv="pragma" content="no-cache">
        <meta http-equiv="cache-control" content="no-cache">
        <meta http-equiv="expires" content="0">   
        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
        <meta http-equiv="description" content="This is my page">
        <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
 
  </head>
 
  <body>
        <form action="LoginAction.action" method="post">
                用户名:<input type="text" name="username">
                密码:<input type="password" name="password">
                书籍1:<input type="text" name="booklist[0].username">
                书籍2:<input type="text" name="booklist[1].username">
                年龄:<input type="text" name="age">
                <input type="submit" value="提交" />
        </form>
  </body>
</html>
4、测试

关于结果处理类型input的代码演示-深入Struts2
            
    
    博客分类: Struts inputStruts2 
 
 
二 通过addFieldError跳回到输入页码,并带错误提示
1、struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd";>
<struts>
        <package name="default" namespace="/" extends="struts-default">
                <default-action-ref name="index"></default-action-ref>
                <action name="index">
                        <result>/error.jsp</result>
                </action>
                
                <action name="*_*_*" method="{2}" class="com.cakin.{3}.{1}Action">
                        <result>/result.jsp</result>
                        <result name="add">/{2}.jsp</result>
                        <result name="update">/{2}.jsp</result>
                </action>
                
                <action name="LoginAction" method="login" class="com.cakin.action.LoginAction">
                        <result>/success.jsp</result>
                        <result name="input">/login.jsp</result>
                </action>
        </package>
</struts>   
2、login.jsp
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
 
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
   
    <title>My JSP 'login.jsp' starting page</title>
   
        <meta http-equiv="pragma" content="no-cache">
        <meta http-equiv="cache-control" content="no-cache">
        <meta http-equiv="expires" content="0">   
        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
        <meta http-equiv="description" content="This is my page">
        <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
 
  </head>
 
  <body>
        <form action="LoginAction.action" method="post">
                用户名:<input type="text" name="username"><s:fielderror name="username"></s:fielderror>
                密码:<input type="password" name="password">
                书籍1:<input type="text" name="booklist[0].username">
                书籍2:<input type="text" name="booklist[1].username">
                年龄:<input type="text" name="age">
                <input type="submit" value="提交" />
        </form>
  </body>
</html>
3、LoginAction
package com.cakin.action;
import com.cakin.po.User;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ModelDriven;
public class LoginAction extends ActionSupport implements ModelDriven<User>{
    private User user =new User();
    public String login(){
        
        if(user.getUsername()==null
                ||"".equals(user.getUsername()))
        {
            this.addFieldError("username", "用户名为空");
            return INPUT;
        }
        
        System.out.println(user.getUsername());
        System.out.println(user.getBooklist().get(0).getUsername());
        System.out.println(user.getBooklist().get(1).getUsername());
        return SUCCESS;
    }
    @Override
    public User getModel() {
        // TODO Auto-generated method stub
        return user;
    }
}
4、测试

关于结果处理类型input的代码演示-深入Struts2
            
    
    博客分类: Struts inputStruts2 
 
三 通过validate方法实现调回到输入页码
1、LoginAction.jsp
package com.cakin.action;
import com.cakin.po.User;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ModelDriven;
public class LoginAction extends ActionSupport implements ModelDriven<User>{
    private User user =new User();
    public String login(){
        
        
        System.out.println(user.getUsername());
        System.out.println(user.getBooklist().get(0).getUsername());
        System.out.println(user.getBooklist().get(1).getUsername());
        return SUCCESS;
    }
    @Override
    public void validate() {
        // TODO Auto-generated method stub
        if(user.getUsername()==null
                ||"".equals(user.getUsername()))
        {
            this.addFieldError("username", "用户名为空");
            //return INPUT;
        }
    }
    @Override
    public User getModel() {
        // TODO Auto-generated method stub
        return user;
    }
}
 
2、测试

关于结果处理类型input的代码演示-深入Struts2
            
    
    博客分类: Struts inputStruts2 
 
  • 关于结果处理类型input的代码演示-深入Struts2
            
    
    博客分类: Struts inputStruts2 
  • 大小: 22.3 KB
  • 关于结果处理类型input的代码演示-深入Struts2
            
    
    博客分类: Struts inputStruts2 
  • 大小: 23.4 KB
相关标签: input Struts2