C#绘制中国象棋棋盘

在c#绘制中国象棋棋盘是c#程序设计中gdi+的一个重要组成部分。这也是非常考验编程技巧的操作。在绘制之前首先要对棋盘有一个完整的认识。下面是完成后的输出图案。

1.在制作过程中用到了背景图片如下：

2.棋盘的横竖交叉线的坐标如下图（棋盘横向、竖向都以50象素间距绘制）

3.更细的坐标分布如下图

完整的代码如下图

using system;
using system.collections.generic;
using system.componentmodel;
using system.data;
using system.drawing;
using system.io;
using system.linq;
using system.text;
using system.threading.tasks;
using system.windows.forms;

namespace chinese_chessboard
{
 public partial class frmmain : form
 {
  public frmmain()
  {
   initializecomponent();
  }

  private void frmmain_paint(object sender, painteventargs e)
  {
   if (!file.exists(application.startuppath + @"\" + "bg.jpg"))
   {
    messagebox.show("请把素材中的bg.jpg图片文件放到可执行程序相同文件夹中,并重新启动程序！", "提示"); application.exit();
   }
   console.writeline("c#编程交流群:485532597");
   graphics g = e.graphics; // 获取一个graphics对象
   g.clear(color.coral);  //用珊瑚色清除窗体
   font font1 = new font("黑体", 25, fontstyle.regular);
   int s = (int)(font1.size / 0.6);
   int s2 = (int)font1.height;
   image img = image.fromfile("bg.jpg");
   g.drawimage(image.fromfile(application.startuppath + @"\" + "bg.jpg"), 10, 10, 430, 480);  //绘制背景图
   g.drawrectangle(new pen(color.black, 3), new rectangle(new point(20, 20), new size(410, 460))); //绘制框图

   pen pen = new pen(color.black, 1);
   //绘制水平线
   for (int i = 0; i < 10; i++)
   {
    g.drawline(pen, new point(25, 25 + (i * 50)), new point(425, 25 + (i * 50)));
   }


   //绘制垂直线
   for (int i = 0; i < 9; i++)
   {
    g.drawline(pen, new point(25 + (i * 50), 25), new point(25 + (i * 50), 225));
    g.drawline(pen, new point(25 + (i * 50), 275), new point(25 + (i * 50), 475));
   }
   //return;
   //绘制将士位置斜线
   g.drawline(pen, new point(175, 25), new point(275, 125));
   g.drawline(pen, new point(275, 25), new point(175, 125));
   g.drawline(pen, new point(175, 375), new point(275, 475));
   g.drawline(pen, new point(175, 475), new point(275, 375));



   //兵位（炮位）线,只画一个
   g.drawline(pen, new point(30, 160), new point(30, 170));
   g.drawline(pen, new point(30, 170), new point(40, 170));
   g.drawline(pen, new point(30, 180), new point(30, 190));
   g.drawline(pen, new point(30, 180), new point(40, 180));

   g.drawstring("楚 河", new font("黑体", 25), brushes.black, new point(50, 235));

   g.translatetransform(300, 235); //平移坐标轴
   g.rotatetransform(180); //进行180度旋转
   g.drawstring("漢 界", new font("黑体", 25), brushes.black, new point(-100, -35));
   g.resettransform(); //坐标轴复位 
   
   this.drawangle(g, pen, new point(125, 175), "all");
   this.drawangle(g, pen, new point(425, 175), "left");
   this.drawangle(g, pen, new point(225, 175), "all");
   this.drawangle(g, pen, new point(425, 175), "left");
   this.drawangle(g, pen, new point(325, 175), "all");
   this.drawangle(g, pen, new point(425, 175), "left");
   this.drawangle(g, pen, new point(75, 125), "all");
   this.drawangle(g, pen, new point(375, 125), "all");

   this.drawangle(g, pen, new point(25, 325), "right");
   this.drawangle(g, pen, new point(125, 325), "all");
   this.drawangle(g, pen, new point(225, 325), "all");
   this.drawangle(g, pen, new point(325, 325), "all");
   this.drawangle(g, pen, new point(425, 325), "left");
   this.drawangle(g, pen, new point(75, 375), "all");
   this.drawangle(g, pen, new point(375, 375), "all");
   g.dispose();   //释放对象
  }
  private void drawangle(graphics g,pen pen, point point,string str)
  {
   point p1 = new point(point.x + 5, point.y + 5);
   point p2= new point(point.x - 5, point.y + 5);
   point p3= new point(point.x -5, point.y - 5);
   point p4 = new point(point.x +5, point.y -5);
   if(str=="right"||str=="all")
   {
    //p1 p4
    g.drawline(pen, p1, new point(p1.x + 10, p1.y));
    g.drawline(pen, p1, new point(p1.x, p1.y+10));
    g.drawline(pen, p4, new point(p4.x + 10, p4.y));
    g.drawline(pen, p4, new point(p4.x, p4.y-10));
   }
   if(str=="left" || str == "all")
   {
    //p2 p3
    g.drawline(pen, p2, new point(p2.x - 10, p2.y));
    g.drawline(pen, p2, new point(p2.x, p2.y+10));
    g.drawline(pen, p3, new point(p3.x - 10, p3.y));
    g.drawline(pen, p3, new point(p3.x, p3.y - 10));
   }
  }
 }
}

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