PHP获取一年有几周以及每周开始日期和结束日期

最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现php获取一年有几周以及每周开始日期和结束日期

代码一：

<?php
header("content-type:text/html;charset=utf-8");
date_default_timezone_set("asia/shanghai");
$year = (int)$_get['year'];
$week = (int)$_get['week'];
$weeks = date("w", mktime(0, 0, 0, 12, 28, $year));
echo $year . '年一共有' . $weeks . '周<br />';
if ($week > $weeks || $week <= 0)
{
 $week = 1;
}
if ($week < 10)
{
 $week = '0' . $week;
}
$timestamp['start'] = strtotime($year . 'w' . $week);
$timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);
echo $year . '年第' . $week . '周开始时间戳：' . $timestamp['start'] . '<br />';
echo $year . '年第' . $week . '周结束时间戳：' . $timestamp['end'] . '<br />';
echo $year . '年第' . $week . '周开始日期：' . date("y-m-d", $timestamp['start']) . '<br />';
echo $year . '年第' . $week . '周结束日期：' . date("y-m-d", $timestamp['end']);
?>

代码二：

<?php
header("content-type:text/html;charset=utf-8");
function getisoweeksinyear($year)
{
 $date = new datetime;
 $date->setisodate($year, 53);
 return ($date->format("w") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
 $week_start = date('d-m-y', strtotime('this week monday', $custom_date));
 $week_end = date('d-m-y', strtotime('this week sunday', $custom_date));
 $week_array[0] = $week_start;
 $week_array[1] = $week_end;
 return $week_array;
}
echo '<br> weeks in 2013<br>' . getisoweeksinyear(2013);
$weekday = weekday(strtotime(date('d-m-y', strtotime('5-8-2013'))));
echo '<br> 10-8-2013';
echo '<br>start: ' . $weekday[0];
echo '<br>end: ' . $weekday[1];
?>

以上本文的全部内容，希望对大家学习php获取一年有几周以及每周开始日期和结束日期，有所帮助。