一款html5 canvas实现的图片玻璃碎片特效_html5教程技巧
程序员文章站
2022-03-11 21:21:54
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今天要为大家带来一款html5 canvas实现的图片玻璃碎片特效。图片以玻璃碎片的形式出现到界面中,然后似玻璃被打碎的效果渐消息。效果图如下:
html代码:
html代码:
代码如下:
<img src="city_copy.jpg" id="src_img" class="hidden"> <p id="container" style="-webkit-perspective: 500px;"> <p> <script src="delaunay.js?1.1.5"></script> <script src="TweenMax.min.js?1.1.5"></script>
js代码:
代码如下:
// canvas settings var imageWidth = 768, imageHeight = 485; var vertices = [], indices, boxes = []; var image, fragments = [], container = document.getElementById('container'); window.onload = function () { image = document.getElementById('src_img'); triangulate(); makeBoxes(); makeFragments(); }; function triangulate() { var x, y, dx = imageWidth / 8, dy = imageHeight / 8, offset = 0.5; for (var i = 0; i <= imageWidth; i += dx) { for (var j = 0; j <= imageHeight; j += dy) { if (i && (i !== imageWidth)) x = i + randomRange(-dx * offset, dx * offset); else x = i; if (j && (j !== imageHeight)) y = j + randomRange(-dy * offset, dy * offset); else y = j; vertices.push([x, y]); } } indices = Delaunay.triangulate(vertices); } function makeBoxes() { var p0, p1, p2, xMin, xMax, yMin, yMax; for (var i = 0; i < indices.length; i += 3) { p0 = vertices[indices[i + 0]]; p1 = vertices[indices[i + 1]]; p2 = vertices[indices[i + 2]]; xMin = Math.min(p0[0], p1[0], p2[0]); xMax = Math.max(p0[0], p1[0], p2[0]); yMin = Math.min(p0[1], p1[1], p2[1]); yMax = Math.max(p0[1], p1[1], p2[1]); boxes.push({ x: xMin, y: yMin, w: xMax - xMin, h: yMax - yMin }); } } function makeFragments() { var p0, p1, p2, box, fragment; TweenMax.set(container, { perspective: 500 }); var tl0 = new TimelineMax({ repeat: -1 }); for (var i = 0; i < indices.length; i += 3) { p0 = vertices[indices[i + 0]]; p1 = vertices[indices[i + 1]]; p2 = vertices[indices[i + 2]]; box = boxes[i / 3]; fragment = new Fragment(p0, p1, p2, box); var rx = randomRange(30, 60) * ((i % 2) ? 1 : -1); var ry = randomRange(30, 60) * ((i % 2) ? -1 : 1); var tl1 = new TimelineMax(); TweenMax.set(fragment.canvas, { y: box.y - 1000 }); tl1.to(fragment.canvas, randomRange(0.9, 1.1), { y: box.y, ease: Back.easeOut }); tl1.to(fragment.canvas, 0.5, { z: -100, ease: Cubic.easeIn, delay: 0.4 }); tl1.to(fragment.canvas, randomRange(1, 1.2), { rotationX: rx, rotationY: ry, z: 250, alpha: 0, ease: Cubic.easeOut }); tl0.insert(tl1); fragments.push(fragment); container.appendChild(fragment.canvas); } } function randomRange(min, max) { return min + (max - min) * Math.random(); } Fragment = function (v0, v1, v2, box) { this.v0 = v0; this.v1 = v1; this.v2 = v2; this.box = box; this.canvas = document.createElement('canvas'); this.canvas.width = this.box.w; this.canvas.height = this.box.h; this.canvas.style.width = this.box.w + 'px'; this.canvas.style.height = this.box.h + 'px'; this.ctx = this.canvas.getContext('2d'); TweenMax.set(this.canvas, { x: this.box.x, y: this.box.y }); this.ctx.translate(-this.box.x, -this.box.y); this.ctx.beginPath(); this.ctx.moveTo(this.v0[0], this.v0[1]); this.ctx.lineTo(this.v1[0], this.v1[1]); this.ctx.lineTo(this.v2[0], this.v2[1]); this.ctx.closePath(); this.ctx.clip(); this.ctx.drawImage(image, 0, 0); }; //@ sourceURL=pen.js
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