opencv实现回形遍历像素算法
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2022-06-24 22:34:04
本文实例为大家分享了opencv实现回形遍历像素算法的具体代码,供大家参考,具体内容如下代码实现# -*- coding:utf-8 -*-import cv2import numpy as np c...
本文实例为大家分享了opencv实现回形遍历像素算法的具体代码,供大家参考,具体内容如下
代码实现
# -*- coding:utf-8 -*- import cv2 import numpy as np cv2.namedwindow('img', 0) def traversepixelbycycloidline(image): """ 从一副灰度图像的中心开始向边缘按回形线的方式遍历所有像素,每个像素只能访问一次。 我目前实现了基本的算法, 但存在以下问题: 1) 只支持方阵, 且行列为奇数 2) 只实现, 代码没整理 """ h, w = image.shape[:2] assert h == w and h % 2 == 1, '只支持方阵, 且行列为奇数' center_x, center_y = [w // 2, h // 2] traverse_num = h * w cycloid_num = 0 value = 1 while true: for i in range(cycloid_num * 2 + 1): if value >= traverse_num: return image center_x = center_x + 1 image[center_y, center_x] = 255 value += 1 cv2.imshow('img', image) cv2.waitkey(33) for i in range(cycloid_num * 2 + 1): if value >= traverse_num: return image center_y = center_y + 1 image[center_y, center_x] = 255 value += 1 cv2.imshow('img', image) cv2.waitkey(33) for i in range(cycloid_num * 2 + 2): if value >= traverse_num: return image center_x = center_x - 1 image[center_y, center_x] = 255 value += 1 cv2.imshow('img', image) cv2.waitkey(33) for i in range(cycloid_num * 2 + 2): if value >= traverse_num: return image center_y = center_y - 1 image[center_y, center_x] = 255 value += 1 cv2.imshow('img', image) cv2.waitkey(33) cycloid_num += 1 image_wh = 11 while true: image = np.zeros((image_wh, image_wh, 3), dtype=np.uint8) traversepixelbycycloidline(image)
效果展示
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。