ajax提交到java后台之后处理数据的实现
程序员文章站
2022-06-24 16:09:50
环境：eclipse+struts
要实现的效果：点击按钮提交数据到后台之后回到前台显示出来数据
index.jsp
<%@ page lang...
环境：eclipse+struts
要实现的效果：点击按钮提交数据到后台之后回到前台显示出来数据
index.jsp
<%@ page language="java" contenttype="text/html; charset=utf-8"
pageencoding="utf-8"%>
<!doctype html public "-//w3c//dtd html 4.01 transitional//en" "http://www.w3.org/tr/html4/loose.dtd">
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<title>insert title here</title>
</head>
<body>
<input type="text" id="userinput">
<input type="button" id="submit">
<div id="msg"></div>
</body>
<script type="text/javascript" src="jquery-2.1.0.js"></script>
<script type="text/javascript">
window.onload = function() {
document.getelementbyid("submit").onclick = test;
}
function test(){
var userinput = document.getelementbyid("userinput");
$.post("http://localhost:8080/testspring/testaction",{username:userinput.value},
function(data, textstatus){
document.getelementbyid("msg").innerhtml = data;
});
}
</script>
</html>
struts.xml
<action name="testaction" class="com.action.test"> <result>index.jsp</result> </action>
test.java
package com.action;
import java.io.printwriter;
import java.util.map;
import javax.servlet.http.httpservletrequest;
import javax.servlet.http.httpservletresponse;
import org.apache.struts2.servletactioncontext;
import com.opensymphony.xwork2.actioncontext;
import com.opensymphony.xwork2.actionsupport;
public class test extends actionsupport {
@override
public string execute() throws exception {
// todo auto-generated method stub
httpservletrequest request = org.apache.struts2.servletactioncontext.getrequest();
httpservletresponse response = servletactioncontext.getresponse();
request.setcharacterencoding("utf-8");
response.setcharacterencoding("utf-8");
printwriter out = response.getwriter();
out.write(request.getparameter("username"));
out.flush();
out.close();
return success;
}
}
以上这篇ajax提交到java后台之后处理数据的实现就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持。
上一篇： AJAX 异步传输数据的问题