欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  IT编程

分享PHP计算两个日期相差天数的代码

程序员文章站 2022-06-23 16:19:27
本文实例讲述了php计算两个日期相差天数的方法。分享给大家供大家参考。具体实现方法如下:

本文实例讲述了php计算两个日期相差天数的方法。分享给大家供大家参考。具体实现方法如下:

<?php
$date1 = date( 'y-m-d' );
$date2 = "2015-12-04";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
-------------------------------------------------------- or
$date1 = new datetime("2007-03-24");
$date2 = new datetime("2009-06-26");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days "; 
// shows the total amount of days (not divided into years, months and days like above)
echo "difference " . $interval->days . " days ";
-------------------------------------------------------- or  
  
/**
 * calculate differences between two dates with precise semantics. based on phps datetime::diff()
 * implementation by derick rethans. ported to php by emil h, 2011-05-02. no rights reserved.
*/
function _date_range_limit($start, $end, $adj, $a, $b, $result)
{
 if ($result[$a] < $start) {
  $result[$b] -= intval(($start - $result[$a] - 1) / $adj) + 1;
  $result[$a] += $adj * intval(($start - $result[$a] - 1) / $adj + 1);
 }
 if ($result[$a] >= $end) {
  $result[$b] += intval($result[$a] / $adj);
  $result[$a] -= $adj * intval($result[$a] / $adj);
 }
 return $result;
}
function _date_range_limit_days($base, $result)
{
 $days_in_month_leap = array(31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
 $days_in_month = array(31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
 _date_range_limit(1, 13, 12, "m", "y", &$base);
 $year = $base["y"];
 $month = $base["m"];
 if (!$result["invert"]) {
  while ($result["d"] < 0) {
   $month--;
   if ($month < 1) {
    $month += 12;
    $year--;
   }
   $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
   $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
   $result["d"] += $days;
   $result["m"]--;
  }
 } else {
  while ($result["d"] < 0) {
   $leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
   $days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
   $result["d"] += $days;
   $result["m"]--;
   $month++;
   if ($month > 12) {
    $month -= 12;
    $year++;
   }
  }
 }
 return $result;
}
function _date_normalize($base, $result)
{
 $result = _date_range_limit(0, 60, 60, "s", "i", $result);
 $result = _date_range_limit(0, 60, 60, "i", "h", $result);
 $result = _date_range_limit(0, 24, 24, "h", "d", $result);
 $result = _date_range_limit(0, 12, 12, "m", "y", $result);
 $result = _date_range_limit_days(&$base, &$result);
 $result = _date_range_limit(0, 12, 12, "m", "y", $result);
 return $result;
}
/**
 * accepts two unix timestamps.
 */
function _date_diff($one, $two)
{
 $invert = false;
 if ($one > $two) {
  list($one, $two) = array($two, $one);
  $invert = true;
 }
 $key = array("y", "m", "d", "h", "i", "s");
 $a = array_combine($key, array_map("intval", explode(" ", date("y m d h i s", $one))));
 $b = array_combine($key, array_map("intval", explode(" ", date("y m d h i s", $two))));
 $result = array();
 $result["y"] = $b["y"] - $a["y"];
 $result["m"] = $b["m"] - $a["m"];
 $result["d"] = $b["d"] - $a["d"];
 $result["h"] = $b["h"] - $a["h"];
 $result["i"] = $b["i"] - $a["i"];
 $result["s"] = $b["s"] - $a["s"];
 $result["invert"] = $invert ? 1 : 0;
 $result["days"] = intval(abs(($one - $two)/86400));
 if ($invert) {
  _date_normalize(&$a, &$result);
 } else {
  _date_normalize(&$b, &$result);
 }
 return $result;
}
$date = "2014-12-04 19:37:22";
echo '<pre>';
print_r( _date_diff( strtotime($date), time() ) );
echo '</pre>'; 
?>

希望本文所述对大家学习php程序设计有所帮助。