Python实现账号密码输错三次即锁定功能简单示例
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2022-06-21 09:21:22
本文实例讲述了python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:
初学python—1
#实现账号输错三次即锁定
user = "h...
本文实例讲述了python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:
初学python—1
#实现账号输错三次即锁定 user = "hubery" passwd = "123" confirm = 0 lock=0 fileopen = open("username.txt","a+") fileopen.seek(0) for i in range(3): username = input("username:") passsword = input("password:") for line in fileopen.readlines(): if username == line.strip(): print("账户已经锁定!") lock=1 break else: continue fileopen.seek(0) if user == username and lock ==0: if passwd == passsword: print("欢迎,欢迎!") confirm = 1 break else: print("账号户或者密码错误!") continue elif lock==1: continue else: print("1账号或者密码错误!") continue fileopen.close() if confirm == 0 and lock==0: filewrite=open("username.txt","a") filewrite.write(username+"\n") filewrite.close()
基本功能可以实现;
锁定的账号为第三次输错的用户名(待完善)
以下为完善版本,如有错误,请告知
import os user = "hubery" passwd = "123" count = 0 lock = 0 fileopen = open("username.txt", "a+") fileopen.seek(0) while 1: for i in range(5): username = input("username:") passsword = input("password:") for line in fileopen.readlines(): if username == line.strip(): print("账户已经锁定!") lock = 1 break else: continue fileopen.seek(0) if user == username: if lock == 1: continue elif passsword == passwd: print("欢迎,欢迎!") os._exit(0) elif count < 2: print("账号或者密码错误!") count += 1 continue else: fileopen.write(username + "\n") fileopen.flush() print("密码输入错误超过三次,账户已经锁定!") fileopen.seek(0) continue else: print("账号密码错误!") continue check=input("还想验证其他账户?(yes-继续,no-退出)") if "no"==check.lower(): os._exit(0) else: continue fileopen.close()
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