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Python实现账号密码输错三次即锁定功能简单示例

程序员文章站 2022-06-21 09:21:22
本文实例讲述了python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下: 初学python—1 #实现账号输错三次即锁定 user = "h...

本文实例讲述了python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:

初学python—1

#实现账号输错三次即锁定
user = "hubery"
passwd = "123"
confirm = 0
lock=0
fileopen = open("username.txt","a+")
fileopen.seek(0)
for i in range(3):
 username = input("username:")
 passsword = input("password:")
 for line in fileopen.readlines():
  if username == line.strip():
   print("账户已经锁定!")
   lock=1
   break
  else:
   continue
 fileopen.seek(0)
 if user == username and lock ==0:
  if passwd == passsword:
   print("欢迎,欢迎!")
   confirm = 1
   break
  else:
   print("账号户或者密码错误!")
   continue
 elif lock==1:
  continue
 else:
  print("1账号或者密码错误!")
  continue
fileopen.close()
if confirm == 0 and lock==0:
 filewrite=open("username.txt","a")
 filewrite.write(username+"\n")
 filewrite.close()

基本功能可以实现;

锁定的账号为第三次输错的用户名(待完善)

以下为完善版本,如有错误,请告知

import os
user = "hubery"
passwd = "123"
count = 0
lock = 0
fileopen = open("username.txt", "a+")
fileopen.seek(0)
while 1:
 for i in range(5):
  username = input("username:")
  passsword = input("password:")
  for line in fileopen.readlines():
   if username == line.strip():
    print("账户已经锁定!")
    lock = 1
    break
   else:
    continue
  fileopen.seek(0)
  if user == username:
   if lock == 1:
    continue
   elif passsword == passwd:
    print("欢迎,欢迎!")
    os._exit(0)
   elif count < 2:
    print("账号或者密码错误!")
    count += 1
    continue
   else:
    fileopen.write(username + "\n")
    fileopen.flush()
    print("密码输入错误超过三次,账户已经锁定!")
    fileopen.seek(0)
    continue
  else:
   print("账号密码错误!")
   continue
 check=input("还想验证其他账户?(yes-继续,no-退出)")
 if "no"==check.lower():
  os._exit(0)
 else:
  continue
fileopen.close()

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