vue form表单post请求结合Servlet实现文件上传功能
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2022-06-19 15:22:02
前端测试页面代码：
前端测试页面代码：
<template>
<div>
<input type="file" name="file" @change="change($event)">
</div>
</template>
<script>
export default {
created(){
this.path = this.$route.query;
for (let i in this.path) {
this[i] = decodeuricomponent(this.path[i]);
}
},
methods:{
change(ev){
let file = ev.target.files[0];
let size = file.size;
let name = file.name;
if(size > 314572800){
this.$message.warning('上传文件不能超过300m');
return;
}
let formdata = new formdata();
formdata.append('file',file,name)
this.$axios.post('/jt3'+this.getddrecorddelete,formdata,{
headers:{"content-type":"multipart/form-data"}
}).then(data=>{
console.log(data);
})
}
}
}
</script>
<style scoped>
</style>
后端servlet接收代码
package jt3.control.zygkh;
import java.io.file;
import java.io.fileoutputstream;
import java.io.ioexception;
import java.io.inputstream;
import java.util.list;
import javax.servlet.servletexception;
import javax.servlet.annotation.webservlet;
import javax.servlet.http.httpservlet;
import javax.servlet.http.httpservletrequest;
import javax.servlet.http.httpservletresponse;
import org.apache.commons.fileupload.fileitem;
import org.apache.commons.fileupload.fileuploadexception;
import org.apache.commons.fileupload.disk.diskfileitemfactory;
import org.apache.commons.fileupload.servlet.servletfileupload;
import jtacc.filter.jtkit;
import jtacc.jtpub.dt;
@webservlet(urlpatterns = "/upfile/file")
public class uploadservlet extends httpservlet {
private static final long serialversionuid = 1l;
protected void doget(httpservletrequest request, httpservletresponse response) throws servletexception, ioexception {
system.out.println(11);
this.dopost(request, response);
}
protected void dopost(httpservletrequest request, httpservletresponse response) throws servletexception, ioexception {
string uri="/u/file/"+dt.getformatdate("yyyymmdd")+"/"; //定义路径
string tmppath=jtkit.getbasedir()+uri;//此处为个人项目路径，根据需求定义路径
diskfileitemfactory factory = new diskfileitemfactory();
factory.setrepository(new file(tmppath));//临时文件存储路径
servletfileupload fileupload = new servletfileupload(factory);//核心操作对象
fileupload.setheaderencoding("utf-8");//防乱码
try {
//此处如果要实时强行转换则需要下载jar包（commons-fileupload-1.3.3.jar）
list<fileitem> list = fileupload.parserequest(request);
for (fileitem fileitem : list) {
inputstream in = fileitem.getinputstream();
string filename = fileitem.getname();
if (fileitem != null) {
system.out.println(filename);
int len = 0;
byte[] array = new byte[1024];
fileoutputstream fos = new fileoutputstream(tmppath+filename);
while((len = in.read(array))!=-1){//表示每次最多读1024个字节
fos.write(array,0,len);
fos.flush();
}
fos.close();
in.close();
fileitem.delete();
response.setcharacterencoding("utf-8");
string realpath = uri+filename;
response.getwriter().append(realpath);
}
}
} catch (fileuploadexception e) {
// todo auto-generated catch block
e.printstacktrace();
}
}
}
测试结果
补充：servlet获取表单提交过来的数据
在servlet的dopost方法：
protected void dopost(httpservletrequest request, httpservletresponse response) throws servletexception, ioexception {
}
中获取表单数据，首先，为了防止出现中文乱码问题，需要给request设置编码为“utf-8”：
request.setcharacterencoding("utf-8");
获取单个字符串的方式：
<pre style="font-family: 宋体; font-size: 12pt; background-color: rgb(255, 255, 255);"><span style="font-size:18px; font-family: arial, helvetica, sans-serif; background-color: rgb(240, 240, 240);">string username = request.getparameter("username");</span>
获取字符串数组的方式：
string[] favorites = request.getparametervalues("favorite");
以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。