这段PHP代码如何写成能输出的结果和JS一样

程序员文章站 2022-06-17 14:15:05

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这段PHP代码怎么写成能输出的结果和JS一样？
下面是我自己转成PHP代码


function na($a) {
    if (!$a) return "";
    $a = (string)$a;
 $h=array(-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,62,-1,-1,-1,63,52,53,54,55,56,57,58,59,60,61,-1,-1,-1,-1,-1,-1,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,-1,-1,-1,-1,-1,-1,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,-1,-1,-1,-1,-1);
    $i = strlen($a);
	$e="";
    for ($f = 0;$f        do {$aa=$a[$f++];$c = $h[ord($aa) & 255];}while ($f         if (-1 == $c) break;
        do {$aa2=$a[$f++];$b = $h[ord($aa2) & 255];} while ($f         if (-1 == $b) break;
        $e += (string)chr($c > 4);
        do{ $aa3=$a[$f++];$c=ord($aa3)&255;if(61==$c)return $e;$c=$h[$c];}while($f        if (-1 == $c) break;
		$e += (string)chr(($b & 15) > 2);
        do{ $aa4=$a[$f++];$b=ord($aa4)&255; if(61==$b)return $e;$b=$h[$b];}while($f        if (-1 == $b) break;
        $e += (string)chr(($c &3)     }
	//echo $e;
    return $e;
}

下面是原JS代码


function na(a) {
    if (!a) return "";
    var a = a.toString(),
        c, b, f, i, e, h = [-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1, -1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1];
    i = a.length;
    f = 0;
    for (e = ""; f         do c = h[a.charCodeAt(f++) & 255]; while (f         if (-1 == c) break;
        do b = h[a.charCodeAt(f++) & 255]; while (f         if (-1 == b) break;
        e += String.fromCharCode(c > 4);
        do {
            c = a.charCodeAt(f++) & 255;
            if (61 == c) return e;
            c = h[c]
        } while (f         if (-1 == c) break;
        e += String.fromCharCode((b & 15) > 2);
        do {
            b = a.charCodeAt(f++) & 255;
            if (61 == b) return e;
            b = h[b]
        } while (f         if (-1 == b) break;
        e += String.fromCharCode((c & 3)     }
    return e
}

我用这个字符串做测试：NAXRSg4bL7zd0vjF8+JxVNXyuUBv1wnLURc=

在PHP测试结果是：4
但在JS里面测试结果是：4?J[email protected] ?Q
不知道哪里错误了这段PHP代码如何写成能输出的结果和JS一样

------解决思路----------------------

function na($a) {
    if (!$a) return "";
    $a = "$a";
    $h = [-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1, -1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1];
    $i = strlen($a);
    $f = 0;
    for ($e = ""; $f         do $c = $h[ord($a{$f++}) & 255]; while ($f         if (-1 == $c) break;
        do $b = $h[ord($a{$f++}) & 255]; while ($f         if (-1 == $b) break;
        $e .= chr($c ------解决思路----------------------
 ($b & 48) >> 4);
        do {
            $c = ord($a{$f++}) & 255;
            if (61 == $c) return $e;
            $c = $h[$c];
        } while ($f         if (-1 == $c) break;
        $e .= chr(($b & 15) ------解决思路----------------------
 ($c & 60) >> 2);
        do {
            $b = ord($a{$f++}) & 255;
            if (61 == $b) return $e;
            $b = $h[$b];
        } while ($f         if (-1 == $b) break;
        $e .= chr(($c & 3) ------解决思路----------------------
 $b);
    }
    return $e;
}

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