phpcms_v9如何在首页显示或排除某些栏目subcat(0,0,0,$siteid)
phpcms_v9如何在首页显示或排除某些栏目subcat(0,0,0,$siteid)
v9如何在首页显示或排除某些栏目subcat(0,0,0,$siteid)
通过以下红色部分的栏目id来控制显示哪些栏目,id根据实际情况后台查询,subcat函数看最后附件解释,以下修改代码:
V9显示哪些栏目的方法
{loop subcat(0,0,0,$siteid) $r}http://blog.csdn.net/a1079540945/article/details/{$r}更多>>
{str_cut($v['description'],100)}
V9排除某个栏目的方法
{loop subcat(0,0,0,$siteid) $r}
{if $r['catid']==3 }{/if} //排除某个栏目http://blog.csdn.net/a1079540945/article/details/{$r}更多>>
{str_cut($v['description'],100)}
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{loop subcat(0,0,0,$siteid) $r}{/loop}函数解释:
{loop subcat(0,0,0,$siteid) $r}{/loop}
/**
* 获取子栏目
* @param $parentid 父级id
* @param $type 栏目类型 1为单网页类型,0为栏目类型;(查看phpcms的mysql数据库可以看到)
* @param $self 是否包含本身 0为不包含
* @param $siteid 站点id
*/
function subcat($parentid = NULL, $type = NULL,$self = '0', $siteid = '') {
if (empty($siteid)) $siteid = get_siteid();
$category = getcache('category_content_'.$siteid,'commons');
foreach($category as $id=>$cat) {
if($cat['siteid'] == $siteid && ($parentid === NULL || $cat['parentid'] == $parentid) && ($type === NULL || $cat['type'] ==
$type)) $subcat[$id] = $cat;
if($self == 1 && $cat['catid'] == $parentid && !$cat['child']) $subcat[$id] = $cat;
}
return $subcat;
}