使用 fastjson 进行json的解析和拼装

fastjson依赖：

<dependency>
            <groupId>com.alibaba</groupId>
            <artifactId>fastjson</artifactId>
            <version>1.2.58</version>
</dependency>

1. 解析json字符串

@org.junit.Test
    public void JsonToString() {
        String jsonString = "{\n" +
                "    \"student\":[{\n" +
                "        \"name\":\"韩信\",\n" +
                "        \"age\":\"18\"\n" +
                "    },\n" +
                "    {\n" +
                "       \"name\":\"阿离\",\n" +
                "       \"age\":\"22\"\n" +
                "   },\n" +
                "   {\n" +
                "       \"name\":\"立华奏\",\n" +
                "       \"age\":\"21\"\n" +
                "   }]\n" +
                "}";

        JSONObject jsonObject = new JSONObject();
        //将json字符串转换为jsonObject
        jsonObject = jsonObject.parseObject(jsonString);
        //获取json
        JSONArray jsonArray = jsonObject.getJSONArray("student");
        for (Object object : jsonArray) {
            JSONObject object1 = (JSONObject)object;
            String name = object1.getString("name");
            String url = object1.getString("age");
            System.out.println(name + url);
        }

    }

输出结果为：

2. 组装json数据

@org.junit.Test
    public void stringTOJson() {
        JSONObject jsonObject = new JSONObject();
        //构建json数组
        JSONArray jsonArray = new JSONArray();
        JSONObject stObject = new JSONObject();
        stObject.put("name","韩信");
        stObject.put("age", "11");
        JSONObject stObject1 = new JSONObject();
        stObject1.put("name","阿离");
        stObject1.put("age", "22");
        jsonArray.add(stObject1);
        jsonObject.put("student", jsonArray);
        System.out.println(jsonObject.toJSONString());

    }

输出结果为: