用python实现双人五子棋（终端版）

五子棋还是有很多大佬发的，今天我也发一篇萌新写的小五子棋
这个是终端版的，如果有问题请大家指出，我去修改
代码如下：

screen = []
screen_change=0

def into():#初始空白棋盘
    for i in range(screen_change):
        list_width=[]
        for j in range(screen_change):
            list_width.append('  '+'  |')
        screen.append(list_width)

def user_black():
    while True:
        coordinate = input("黑方请输入你想填下子的坐标  例1,2或者5,5")
        coordinate=coordinate.split(',')
        width_num = int(coordinate[0]) - 1
        high_num = int(coordinate[1]) - 1
        if screen[width_num][high_num][1]!=' ':
            print('你输入的地方已经有棋子了，请重新输入')
            continue
        screen[width_num][high_num] = ' ' + '@' + '  |'
        break
    screen_print()

def user_white():
    while True:
        coordinate = input("白方请输入你想填下子的坐标  例1,2或者5,5")
        coordinate = coordinate.split(',')
        width_num = int(coordinate[0]) - 1
        high_num = int(coordinate[1]) - 1
        if screen[width_num][high_num][1] != ' ':
            print('你输入的地方已经有棋子了，请重新输入')
            continue
        screen[width_num][high_num] = ' ' + '#' + '  |'
        break
    screen_print()

def eeferee():#判断输赢
    #判断行
    for i in range(screen_change):
        for j in range(screen_change-4):
            if screen[i][j][1]==screen[i][j+1][1]==screen[i][j+2][1]==screen[i][j+3][1]==screen[i][j+4][1] and screen[i][j][1]!=' ':
                return False
    for i in range(screen_change - 4):
        for j in range(screen_change):
            if screen[i][j][1]==screen[i+1][j][1]==screen[i+2][j][1]==screen[i+3][j][1]==screen[i+4][j][1] and screen[i][j][1]!=' ':
                return False
    for i in range(screen_change - 4):
        for j in range(screen_change - 4):
            if screen[i][j][1]==screen[i+1][j+1][1]==screen[i+2][j+2][1]==screen[i+3][j+3][1]==screen[i+4][j+4][1] and screen[i][j][1]!=' ':
                return False
        for k in range(4,screen_change):
            if k>=4:
                if screen[i][k][1] == screen[i+1][k-1][1] == screen[i+2][k-2][1] == screen[i+3][k-3][1] == screen[i+4][k-4][1] and screen[i][k][1] != ' ':
                    return False
    return True

def screen_print():#打印棋盘
    print('——' * (screen_change*3+1))
    for i in range(screen_change):
        print('|',end=' ')
        for j in range(screen_change):
            print(screen[i][j],end=' ')
        print()
        print('——'*(screen_change*3+1))

def main():
    global screen_change
    screen_change = int(input('请输入你设定的棋盘大小：'))
    into()
    screen_print()
    while eeferee():
        user_black()
        if not eeferee():
            break
        user_white()
    print('游戏结束')

if __name__=='__main__':
    main()

效果图如下：

Python问题解答私信我

本文地址：https://blog.csdn.net/Miku_wx/article/details/111831268