MySQL的rank函数实现_MySQL

Mysql 的rank 函数如何实现 - 大鸟的学习乐园 - BlogJava

http://www.blogjava.net/dunkbird/archive/2011/01/28/343718.html

表特征：

mysql> select * from test;

+------+------+
| a | b |
+------+------+
| 1 | 20 |
| 1 | 21 |
| 1 | 24 |
| 2 | 20 |
| 2 | 32 |
| 2 | 14 |
+------+------+
6 rows in set (0.00 sec)

现在，我们以a分组，查询b列最大的2个值。 这条sql要怎么写了？

1.创建表

Create Table: CREATE TABLE `sam` (  `a` int(11) DEFAULT NULL,  `b` int(11) DEFAULT NULL) ENGINE=MyISAM DEFAULT CHARSET=utf8

2.插入模拟数据

INSERT INTO `sam` VALUES (1,10),(1,15),(1,20),(1,25),(2,20),(2,22),(2,33),(2,45);

+------+------+
| a | b |
+------+------+
| 1 | 10 |
| 1 | 15 |
| 1 | 20 |
| 1 | 25 |
| 2 | 20 |
| 2 | 22 |
| 2 | 33 |
| 2 | 45 |
+------+------+

3.SQL实现

select a,b,rownum,rank from     (select ff.a,ff.b,@rownum:=@rownum+1 rownum,if(@pa=ff.a,@rank:=@rank+1,@rank:=1) as rank,@pa:=ff.a     FROM       (select a,b from sam group by a,b order by a asc,b desc) ff,(select @rank:=0,@rownum:=0,@pa=null) tt) result    having rank 
4.结果：
+------+------+--------+------+
| a    | b    | rownum | rank |
+------+------+--------+------+
|    1 |   25 |      1 |    1 | 
|    1 |   20 |      2 |    2 | 
|    2 |   45 |      5 |    1 | 
|    2 |   33 |      6 |    2 | 
+------+------+--------+------+
4 rows in set (0.00 sec)
注：
@x 为一变量，
X:=Y 将Y值赋给X