Scala_可变数组,列表,可变集,元组
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2022-06-14 18:56:11
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object demo1{
import scala.collection.mutable.ArrayBuffer//导入变长数组模块
import scala.collection.mutable.ListBuffer//导入可变列表模块
import scala.collection.mutable.Set
def main(args: Array[String]) {
//数组
val ArrayA = ArrayBuffer[Int]()
val ArrayB = ArrayBuffer("python","scala","java","C#")
for(i<-ArrayB) println(i)
//增加一个数据:
ArrayB+="hadoop"
println(ArrayB)
//减少一条数据:
ArrayB-="C#"
println(ArrayB)
//追加数组进入:
ArrayB++=Array("C","MatlaArrayB","SAS")
println(ArrayB)
//修改元素:
ArrayB(0)="PYTHON"
println(ArrayB)
//遍历数组for:
for(i<-0 to ArrayB.length-1){
print(ArrayB(i)+",")
}
println()
for(i<-0 until ArrayB.length){
print(ArrayB(i)+",")
}
println()
ArrayA++=Array(1,4,3,9,11,6)//合并
println(ArrayA.sum,ArrayA.max,ArrayA.min)//最大,最小,求和
println(ArrayA.sorted)//升序
println(ArrayA.sorted.reverse)//降序
//元组tuple
val tupleA =(1,"yanyi",23,"chengdu")
val tupleB = "xiaoArrayBao" -> 22
//访问元组元素:元组是个整体,遍历需要使用迭代器:
for(item <- tupleA.productIterator){
println(item)
}
//列表
//不可变列表
val list1 = (1,2,3,4,5)
val list2 = Nil//创建空列表
val list3 = "hello"::"world"::Nil//两个元素的列表
println(list3)
//可变列表
val list4 = ListBuffer[Int]()
val list5 = ListBuffer(1,2,3,4,5,6,7,8,9)
println(list5+=81)
list5 ++= List(82,83,84)
println(list5)
//转换为不可变列表,数组
val temp1 = list5.toList
val temp2 = list5.toArray
println(temp1.getClass,temp2.getClass)
//可变集
val setA = Set(1,2,3,4,5)
setA +=10//不保证插入位置
setA -= 1
}
}
结果如下:
python
scala
java
C#
ArrayBuffer(python, scala, java, C#, hadoop)
ArrayBuffer(python, scala, java, hadoop)
ArrayBuffer(python, scala, java, hadoop, C, MatlaArrayB, SAS)
ArrayBuffer(PYTHON, scala, java, hadoop, C, MatlaArrayB, SAS)
PYTHON,scala,java,hadoop,C,MatlaArrayB,SAS,
PYTHON,scala,java,hadoop,C,MatlaArrayB,SAS,
(34,11,1)
ArrayBuffer(1, 3, 4, 6, 9, 11)
ArrayBuffer(11, 9, 6, 4, 3, 1)
1
yanyi
23
chengdu
List(hello, world)
ListBuffer(1, 2, 3, 4, 5, 6, 7, 8, 9, 81)
ListBuffer(1, 2, 3, 4, 5, 6, 7, 8, 9, 81, 82, 83, 84)
(class scala.collection.immutable.$colon$colon,class [I)
Set(5, 2, 3, 10, 4)
环境:linux:centos8
文件:demo1.scala
编译步骤:
(zzjz) [[email protected] scala-learn]# scalac demo1.scala
(zzjz) [[email protected] scala-learn]# scala demo1
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