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oracle—SQL技巧之(一)连续记录查询sql案例测试

程序员文章站 2022-06-14 10:05:13
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有这样一个需求:需要查询出某个客户某一年那些天是有连续办理过业务,本文给予sql实现语句并测试,感兴趣的朋友可以了解下

需求说明
需要查询出某个客户某一年那些天是有连续办理过业务

实现SQL如下
创建表:
代码如下:
create table test_num
(tyear number,
tdate date);

测试数据
insert into test_num
select 2014,trunc(sysdate)-1 from dual union all
select 2014,trunc(sysdate)-002 from dual union all
select 2014,trunc(sysdate)-003 from dual union all
select 2014,trunc(sysdate)-004 from dual union all
select 2014,trunc(sysdate)-005 from dual union all
select 2014,trunc(sysdate)-007 from dual union all
select 2014,trunc(sysdate)-008 from dual union all
select 2014,trunc(sysdate)-009 from dual union all
select 2013,trunc(sysdate)-120 from dual union all
select 2013,trunc(sysdate)-121 from dual union all
select 2013,trunc(sysdate)-122 from dual union all
select 2013,trunc(sysdate)-124 from dual union all
select 2013,trunc(sysdate)-125 from dual union all
select 2013,trunc(sysdate)-127 from dual union all
select 2015,trunc(sysdate)-099 from dual union all
select 2015,trunc(sysdate)-100 from dual union all
select 2015,trunc(sysdate)-101 from dual union all
select 2015,trunc(sysdate)-102 from dual union all
select 2015,trunc(sysdate)-104 from dual union all
select 2015,trunc(sysdate)-105 from dual;

写SQL:
代码如下:
SELECT TYEAR, MIN(TDATE) AS STARTDATE, MAX(TDATE), COUNT(TYEAR) AS ENDNUM
FROM (SELECT A.*, A.TDATE - ROWNUM AS GNUM
FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR, TDATE) A)
GROUP BY TYEAR, GNUM
ORDER BY TYEAR, MIN(TDATE)