欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

2000年诺贝尔文学奖 计算2000年01月01日起到指定日的天数

程序员文章站 2022-06-13 20:07:57
...
这是一个计算2000年01月01日起到指定日的天数的函数


(算头也算尾)日期格式为:YYYY-MM-DD


// 计算从2000年01月01日开始到某日的天数
function cal_start2end($end_day,$start_day)
{
$start_day=ereg_replace("-","",$start_day);
$end_day=ereg_replace("-","",$end_day);
if($end_day>=$start_day)
{ // 截止日期大于开始日期
if(substr($end_day,0,4)==substr($start_day,0,4))
{
if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;
// //同一年
if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$end_day-$start_day+1;
}
else
{
// not same month
switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
}
$endday_from_startday=$endday_from_newyear;
}
return ($endday_from_startday);
}
else
{
// 不同年!
$differ_year=substr($end_day,0,4)-substr($start_day,0,4);
$how_int_4_floor=floor($differ_year/4)+1; // 向下取整
$how_int_4_ceil=ceil($differ_year/4)+1; // 向上取整
if($how_int_4_floor==$how_int_4_ceil)
$how_leap_year=$how_int_4_floor-1;
else
$how_leap_year=$how_int_4_floor;
$how_noleap_year=$differ_year-$how_leap_year;
$differ_year2day=$how_noleap_year*365+$how_leap_year*366;
if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;
if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$differ_year2day+ substr($end_day,4,2);
}
else
{
// not same month
switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+1+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
} //End of switch
$endday_from_startday=$endday_from_newyear+$differ_year2day;
} //End of not same month
return ($endday_from_startday);
} //End of year
} //End of $end_day>=$start_day
} //End of function
$start_day="2000-01-01";
$end_day="2011-01-01";
echo "您输入的是:".$end_day."
\n";
$endday_from_startday=cal_start2end($end_day,$start_day);
echo "该日距离$start_day 共 ".$endday_from_startday." 天";
?>




时间太少了,那位大虾可以修改为计算任意两日期之间的间隔最好!!!!!

以上就介绍了2000年诺贝尔文学奖 计算2000年01月01日起到指定日的天数,包括了2000年诺贝尔文学奖方面的内容,希望对PHP教程有兴趣的朋友有所帮助。