欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

Uncaught transport.js/parseResult() error: can't parse to JSON.

程序员文章站 2022-06-13 16:56:29
...
复选框:

按钮:

function check()
{
  var rec_id_Array = new Array();
  $("[name='checkboxes']:checked").each(function () {
  rec_id_Array.push($(this).val());
  });
  listTable.remove(rec_id_Array, '確定拆分訂單嗎', 'split_order');
}

listTable.remove = function(id, cfm, opt)
{
  if (opt == null)
  {
    opt = "remove";
  }

  if (confirm(cfm))
  {
    var args = "act=" + opt + "&id=" + id + this.compileFilter();

    Ajax.call(this.url, args, this.listCallback, "GET", "JSON");
  }
}

回复内容:

复选框:

按钮:

function check()
{
  var rec_id_Array = new Array();
  $("[name='checkboxes']:checked").each(function () {
  rec_id_Array.push($(this).val());
  });
  listTable.remove(rec_id_Array, '確定拆分訂單嗎', 'split_order');
}

listTable.remove = function(id, cfm, opt)
{
  if (opt == null)
  {
    opt = "remove";
  }

  if (confirm(cfm))
  {
    var args = "act=" + opt + "&id=" + id + this.compileFilter();

    Ajax.call(this.url, args, this.listCallback, "GET", "JSON");
  }
}
相关标签: php ajax jquery