python实现决策树分类(2)
程序员文章站
2022-06-11 18:02:23
在中,我们已经构建了决策树,接下来可以使用它用于实际的数据分类。在执行数据分类时,需要决策时以及标签向量。程序比较测试数据和决策树上的数值,递归执行直到进入叶子节点。
这...
在中,我们已经构建了决策树,接下来可以使用它用于实际的数据分类。在执行数据分类时,需要决策时以及标签向量。程序比较测试数据和决策树上的数值,递归执行直到进入叶子节点。
这篇文章主要使用决策树分类器就行分类,数据集采用uci数据库中的红酒,白酒数据,主要特征包括12个,主要有非挥发性酸,挥发性酸度, 柠檬酸, 残糖含量,氯化物, 游离二氧化硫, 总二氧化硫,密度, ph,硫酸盐,酒精, 质量等特征。
下面是具体代码的实现:
#coding :utf-8 ''' 2017.6.26 author :erin function: "decesion tree" id3 ''' import numpy as np import pandas as pd from math import log import operator import random def load_data(): red = [line.strip().split(';') for line in open('e:/a/winequality-red.csv')] white = [line.strip().split(';') for line in open('e:/a/winequality-white.csv')] data=red+white random.shuffle(data) #打乱data x_train=data[:800] x_test=data[800:] features=['fixed','volatile','citric','residual','chlorides','free','total','density','ph','sulphates','alcohol','quality'] return x_train,x_test,features def cal_entropy(dataset): numentries = len(dataset) labelcounts = {} for featvec in dataset: label = featvec[-1] if label not in labelcounts.keys(): labelcounts[label] = 0 labelcounts[label] += 1 entropy = 0.0 for key in labelcounts.keys(): p_i = float(labelcounts[key]/numentries) entropy -= p_i * log(p_i,2)#log(x,10)表示以10 为底的对数 return entropy def split_data(data,feature_index,value): ''' 划分数据集 feature_index:用于划分特征的列数,例如“年龄” value:划分后的属性值:例如“青少年” ''' data_split=[]#划分后的数据集 for feature in data: if feature[feature_index]==value: refeature=feature[:feature_index] refeature.extend(feature[feature_index+1:]) data_split.append(refeature) return data_split def choose_best_to_split(data): ''' 根据每个特征的信息增益,选择最大的划分数据集的索引特征 ''' count_feature=len(data[0])-1#特征个数4 #print(count_feature)#4 entropy=cal_entropy(data)#原数据总的信息熵 #print(entropy)#0.9402859586706309 max_info_gain=0.0#信息增益最大 split_fea_index = -1#信息增益最大,对应的索引号 for i in range(count_feature): feature_list=[fe_index[i] for fe_index in data]#获取该列所有特征值 ####################################### # print(feature_list) unqval=set(feature_list)#去除重复 pro_entropy=0.0#特征的熵 for value in unqval:#遍历改特征下的所有属性 sub_data=split_data(data,i,value) pro=len(sub_data)/float(len(data)) pro_entropy+=pro*cal_entropy(sub_data) #print(pro_entropy) info_gain=entropy-pro_entropy if(info_gain>max_info_gain): max_info_gain=info_gain split_fea_index=i return split_fea_index ################################################## def most_occur_label(labels): #sorted_label_count[0][0] 次数最多的类标签 label_count={} for label in labels: if label not in label_count.keys(): label_count[label]=0 else: label_count[label]+=1 sorted_label_count = sorted(label_count.items(),key = operator.itemgetter(1),reverse = true) return sorted_label_count[0][0] def build_decesion_tree(dataset,featnames): ''' 字典的键存放节点信息,分支及叶子节点存放值 ''' featname = featnames[:] ################ classlist = [featvec[-1] for featvec in dataset] #此节点的分类情况 if classlist.count(classlist[0]) == len(classlist): #全部属于一类 return classlist[0] if len(dataset[0]) == 1: #分完了,没有属性了 return vote(classlist) #少数服从多数 # 选择一个最优特征进行划分 bestfeat = choose_best_to_split(dataset) bestfeatname = featname[bestfeat] del(featname[bestfeat]) #防止下标不准 decisiontree = {bestfeatname:{}} # 创建分支,先找出所有属性值,即分支数 allvalue = [vec[bestfeat] for vec in dataset] specvalue = sorted(list(set(allvalue))) #使有一定顺序 for v in specvalue: copyfeatname = featname[:] decisiontree[bestfeatname][v] = build_decesion_tree(split_data(dataset,bestfeat,v),copyfeatname) return decisiontree def classify(tree, featnames, x): classlabel='' root = list(tree.keys())[0] firstdict = tree[root] featindex = featnames.index(root) #根节点的属性下标 #classlabel='0' for key in firstdict.keys(): #根属性的取值,取哪个就走往哪颗子树 if x[featindex] == key: if type(firstdict[key]) == type({}): classlabel = classify(firstdict[key],featnames,x) else: classlabel = firstdict[key] return classlabel if __name__ == '__main__': x_train,x_test,features=load_data() split_fea_index=choose_best_to_split(x_train) newtree=build_decesion_tree(x_train,features) #print(newtree) #classlabel=classify(newtree, features, ['7.4','0.66','0','1.8','0.075','13','40','0.9978','3.51','0.56','9.4','5'] ) #print(classlabel) count=0 for test in x_test: label=classify(newtree, features,test) if(label==test[-1]): count=count+1 acucy=float(count/len(x_test)) print(acucy)
测试的准确率大概在0.7左右。至此决策树分类算法结束。本文
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