Spring Data JPA与PostgreSQL的jsonb类型集成与支持
程序员文章站
2022-03-10 16:46:01
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在我们项目中经常会遇到数据结构不定的情况,这时普通的关系型数据库不能满足我们的要求。Postgres为我们提供了jsonb
数据类型,我们可在此类型的字段存储json
数据,并可对此数据进行查询。本例将结合hibernate
,Spring Data JPA
,Spring Boot
来实现。
1. 自定义方言
public class JsonbPostgresDialect extends PostgreSQL94Dialect {
public JsonbPostgresDialect() {
this.registerColumnType(Types.JAVA_OBJECT,"jsonb");
}
}
指定方言
spring.jpa.database-platform: com.example.jpajsonb.support.JsonbPostgresDialect
2. 自定义jsonb数据类型
这里主要实现了Map
映射PGObject
(postgres对象类型),通过ObjectMapper
来实现两个数据类型的转换。
public class JsonbType implements UserType{
private final ObjectMapper mapper = new ObjectMapper();;
@Override
public void nullSafeSet(PreparedStatement st, Object value, int index, SessionImplementor session) throws HibernateException, SQLException {
if (value == null) {
st.setNull(index, Types.OTHER);
} else {
try{
st.setObject(index, mapper.writeValueAsString(value), Types.OTHER);
}catch (IOException e){
e.printStackTrace();
}
}
}
@Override
public Object deepCopy(Object originalValue) throws HibernateException {
if (originalValue != null) {
try {
return mapper.readValue(mapper.writeValueAsString(originalValue),
returnedClass());
} catch (IOException e) {
throw new HibernateException("Failed to deep copy object", e);
}
}
return null;
}
@Override
public Object nullSafeGet(ResultSet rs, String[] names, SessionImplementor session, Object owner) throws HibernateException, SQLException {
PGobject o = (PGobject) rs.getObject(names[0]);
if (o.getValue() != null) {
try {
return mapper.readValue(o.getValue(),Map.class);
}catch (IOException e){
e.printStackTrace();
}
}
return new HashMap<String, Object>();
}
@Override
public Serializable disassemble(Object value) throws HibernateException {
Object copy = deepCopy(value);
if (copy instanceof Serializable) {
return (Serializable) copy;
}
throw new SerializationException(String.format("Cannot serialize '%s', %s is not Serializable.", value, value.getClass()), null);
}
@Override
public Object assemble(Serializable cached, Object owner) throws HibernateException {
return deepCopy(cached);
}
@Override
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return deepCopy(original);
}
@Override
public boolean isMutable() {
return true;
}
@Override
public int hashCode(Object x) throws HibernateException {
if (x == null) {
return 0;
}
return x.hashCode();
}
@Override
public boolean equals(Object x, Object y) throws HibernateException {
return ObjectUtils.nullSafeEquals(x, y);
}
@Override
public Class<?> returnedClass() {
return Map.class;
}
@Override
public int[] sqlTypes() {
return new int[]{Types.JAVA_OBJECT};
}
}
3. 声明使用
先定义数据类型,再在字段上使用
@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
@TypeDef(name = "JsonbType", typeClass = JsonbType.class)
public class Person {
@Id
@GeneratedValue
private Long id;
@Column(columnDefinition = "jsonb")
@Type(type = "JsonbType")
private Map<String,Object> info;
}
4.Repository
通过postgres
原生sql语句查询,本例含义为json
数据info
的一个key
为name
的值等于。具体的JSON的sql查询方式请参考:
https://www.postgresql.org/docs/9.5/static/functions-json.html
public interface PersonRepository extends JpaRepository<Person,Long> {
@Query(value = "select * from person where info ->> 'name' = :name" , nativeQuery = true)
List<Person> findByName(@Param("name") String name);
}
5. 保存和读取测试
@Bean
CommandLineRunner saveAndReadJsonb(PersonRepository personRepository){
return e -> {
Person p = new Person();
Map m = new HashMap();
m.put("name","汪云飞");
m.put("age",11);
p.setInfo(m);
Person returnPerson = personRepository.save(p);
Map returnMap = returnPerson.getInfo();
for(Object entry :returnMap.entrySet()){
log.info(entry.toString());
}
};
}
6. 查询测试
@Bean
CommandLineRunner queryJsonb(PersonRepository personRepository){
return e -> {
List<Person> people = personRepository.findByName("吴亦凡");
for (Person person : people){
Map info = person.getInfo();
log.info(person.getId() + "/" + info.get("name") + "/" +info.get("age"));
}
};
}
7. 源码地址
http://www.wisely.top/2017/06/27/spring-data-jpa-postgresql-jsonb/