thinkPHP连表问题,大家进来看看,谢谢了。
程序员文章站
2022-06-10 17:57:05
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join('__COUNTS__ ON __CHOICES__.id = __COUNTS__.cid AND __CHOICES__.vid = __COUNTS__.vid')->order($order)->select();是什么意思,我看不懂,求解释,谢谢了。
回复讨论(解决方案)
相当这样
... inner join counts on choice.id = counts.cid and choices.vid = counts.vid order by $order;
__COUNTS__ 若是有设置表前缀的话,会自动加上 如 t_ 那么 __COUNTS__ 解析后就是 t_counts