sql中字符串分割函数

在sql中没有系统带的的字符分割函数，我们利用了一些功能字了一个分割函数有需要的同学可以参考一下。

代码如下

复制代码

SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO /*by kudychen 2011-9-28 */ CREATE function [dbo].[SplitString] ( @Input nvarchar(max), --input string to be separated @Separator nvarchar(max)=',', --a string that delimit the substrings in the input string @RemoveEmptyEntries bit=1 --the return value does not include array elements that contain an empty string ) returns @TABLE table ( [Id] int identity(1,1), [Value] nvarchar(max)) as begin declare @Index int, @Entry nvarchar(max) set @Index = charindex(@Separator,@Input) while (@Index>0) begin set @Entry=ltrim(rtrim(substring(@Input, 1, @Index-1))) if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry'') begin insert into @TABLE([Value]) Values(@Entry) end set @Input = substring(@Input, @Index+datalength(@Separator)/2, len(@Input)) set @Index = charindex(@Separator, @Input) end set @Entry=ltrim(rtrim(@Input)) if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry'') begin insert into @TABLE([Value]) Values(@Entry) end return end

Test Code:

代码如下	复制代码
declare @str1 varchar(max), @str2 varchar(max), @str3 varchar(max) set @str1 = '1,2,3' set @str2 = '1###2###3' set @str3 = '1###2###3###' [Value] from [dbo].[SplitString](@str1, ',', 1) select [Value] from [dbo].[SplitString](@str2, '###', 1) select [Value] from [dbo].[SplitString](@str3, '###', 0)

Code:

代码如下

复制代码

SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO /*by kudychen 2011-9-28 */ CREATE function [dbo].[SplitString] ( @Input nvarchar(max), --input string to be separated @Separator nvarchar(max)=',', --a string that delimit the substrings in the input string @RemoveEmptyEntries bit=1 --the return value does not include array elements that contain an empty string ) returns @TABLE table ( [Id] int identity(1,1), [Value] nvarchar(max)) as begin declare @Index int, @Entry nvarchar(max) set @Index = charindex(@Separator,@Input) while (@Index>0) begin set @Entry=ltrim(rtrim(substring(@Input, 1, @Index-1))) if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry'') begin insert into @TABLE([Value]) Values(@Entry) end set @Input = substring(@Input, @Index+datalength(@Separator)/2, len(@Input)) set @Index = charindex(@Separator, @Input) end set @Entry=ltrim(rtrim(@Input)) if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry'') begin insert into @TABLE([Value]) Values(@Entry) end return end

Test Code:

代码如下	复制代码
declare @str1 varchar(max), @str2 varchar(max), @str3 varchar(max) set @str1 = '1,2,3' set @str2 = '1###2###3' set @str3 = '1###2###3###' select [Value] from [dbo].[SplitString](@str1, ',', 1) select [Value] from [dbo].[SplitString](@str2, '###', 1) select [Value] from [dbo].[SplitString](@str3, '###', 0)