sql获取指定时间段数据的语句

例如给定一个日期 2010-09-01，求出它所在星期的星期一是2010-08-30，星期天是2010-09-05

代码如下

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Function创建如下: USE [MSSQL] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME) RETURNS @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME) AS BEGIN INSERT INTO @tmpTable SELECT a.FirstDay,b.EndDay FROM ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy ) a LEFT JOIN ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay ) b ON a.ID = b.ID RETURN END Function测试: SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')

二、以上面单个日期搜索为基础，由用户输入两个参数，一个是开始日期，一个结束日期，根据这两个参数，求出在此时期段内的所有星期的星期一和星期天的日期表并排序。
例如开始日期是2011-09-01,结束日期是2011-10-06，我们就可以得到此星期表如下:
WeekOrder FirstDay EndDay
1 2011-08-29 00:00:00.000 2011-09-04 00:00:00.000
2 2011-09-05 00:00:00.000 2011-09-11 00:00:00.000
3 2011-09-12 00:00:00.000 2011-09-18 00:00:00.000
4 2011-09-19 00:00:00.000 2011-09-25 00:00:00.000
5 2011-09-26 00:00:00.000 2011-10-02 00:00:00.000
6 2011-10-03 00:00:00.000 2011-10-09 00:00:00.000

代码如下

复制代码

Function创建如下: USE [MSSQL] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME) RETURNS @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME) AS BEGIN DECLARE @tmpDate DATETIME DECLARE @index INT SET @tmpDate=@tmpDateSTART SET @index=1 WHILE @tmpDate BEGIN INSERT INTO @tmpTable SELECT @index,a.FirstDay,b.EndDay FROM ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a LEFT JOIN ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b ON a.ID = b.ID SET @tmpDate=DATEADD(DAY,7,@tmpDate) SET @index=@index+1 END RETURN END Function测试: SELECT * from My_Range_GetWeekFirstAndEndDays('2011-09-01','2011-10-06')