js比较两个单独的数组或对象是否相等的实例代码
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2022-06-09 14:34:21
所谓js的中的传值,其实也就是说5种基本数据类型(null,undefind,boolean,number,string)
传引用也就是说的那个引用数据类型,(array...
所谓js的中的传值,其实也就是说5种基本数据类型(null,undefind,boolean,number,string)
传引用也就是说的那个引用数据类型,(array和object)
基本数据类型的值不可变,而引用数据类型的值是可变的
所以当你比较数组和对象时,都是false;除非你是克隆的原份数据
即: var a = { name: "李四" }; var b = a;
大家通常称对象为引用类型,以此来和基本类型进行区分; 而对象值都是引用,所以的对象的比较也叫引用的比较,当且当他们都指向同一个引用时,即都引用的同一个基对象时,它们才相等.
1.比较两个单独的数组是否相等
json.stringify(a1) == json.stringify(a2)
或
a1.tostring() == a2.tostring()
要判断2个数组是否相同,把数组转换成字符串进行比较。
如果要比较两个数组的元素是否相等,则:
json.stringify([1,2,3].sort()) === json.stringify([3,2,1].sort());
或
[1,2,3].sort().tostring() === [3,2,1].sort().tostring();
判断2个数组是否相同,首先要把数组进行排序,然后转换成字符串进行比较。
2.比较两个单独的对象是否相等
let cmp = ( x, y ) => { // if both x and y are null or undefined and exactly the same if ( x === y ) { return true; } // if they are not strictly equal, they both need to be objects if ( ! ( x instanceof object ) || ! ( y instanceof object ) ) { return false; } //they must have the exact same prototype chain,the closest we can do is //test the constructor. if ( x.constructor !== y.constructor ) { return false; } for ( var p in x ) { //inherited properties were tested using x.constructor === y.constructor if ( x.hasownproperty( p ) ) { // allows comparing x[ p ] and y[ p ] when set to undefined if ( ! y.hasownproperty( p ) ) { return false; } // if they have the same strict value or identity then they are equal if ( x[ p ] === y[ p ] ) { continue; } // numbers, strings, functions, booleans must be strictly equal if ( typeof( x[ p ] ) !== "object" ) { return false; } // objects and arrays must be tested recursively if ( ! object.equals( x[ p ], y[ p ] ) ) { return false; } } } for ( p in y ) { // allows x[ p ] to be set to undefined if ( y.hasownproperty( p ) && ! x.hasownproperty( p ) ) { return false; } } return true; };
下面是*大神封装的方法,可以学习一下:
1.比较数组
// warn if overriding existing method if(array.prototype.equals) console.warn("overriding existing array.prototype.equals. possible causes: new api defines the method, there's a framework conflict or you've got double inclusions in your code."); // attach the .equals method to array's prototype to call it on any array array.prototype.equals = function (array) { // if the other array is a falsy value, return if (!array) return false; // compare lengths - can save a lot of time if (this.length != array.length) return false; for (var i = 0, l = this.length; i < l; i++) { // check if we have nested arrays if (this[i] instanceof array && array[i] instanceof array) { // recurse into the nested arrays if (!this[i].equals(array[i])) return false; } else if (this[i] != array[i]) { // warning - two different object instances will never be equal: {x:20} != {x:20} return false; } } return true; } // hide method from for-in loops object.defineproperty(array.prototype, "equals", {enumerable: false});
2.比较对象
object.prototype.equals = function(object2) { //for the first loop, we only check for types for (propname in this) { //check for inherited methods and properties - like .equals itself //https://developer.mozilla.org/en-us/docs/web/javascript/reference/global_objects/object/hasownproperty //return false if the return value is different if (this.hasownproperty(propname) != object2.hasownproperty(propname)) { return false; } //check instance type else if (typeof this[propname] != typeof object2[propname]) { //different types => not equal return false; } } //now a deeper check using other objects property names for(propname in object2) { //we must check instances anyway, there may be a property that only exists in object2 //i wonder, if remembering the checked values from the first loop would be faster or not if (this.hasownproperty(propname) != object2.hasownproperty(propname)) { return false; } else if (typeof this[propname] != typeof object2[propname]) { return false; } //if the property is inherited, do not check any more (it must be equa if both objects inherit it) if(!this.hasownproperty(propname)) continue; //now the detail check and recursion //this returns the script back to the array comparing /**requires array.equals**/ if (this[propname] instanceof array && object2[propname] instanceof array) { // recurse into the nested arrays if (!this[propname].equals(object2[propname])) return false; } else if (this[propname] instanceof object && object2[propname] instanceof object) { // recurse into another objects //console.log("recursing to compare ", this[propname],"with",object2[propname], " both named \""+propname+"\""); if (!this[propname].equals(object2[propname])) return false; } //normal value comparison for strings and numbers else if(this[propname] != object2[propname]) { return false; } } //if everything passed, let's say yes return true; }
总结
以上所述是小编给大家介绍的js比较两个单独的数组或对象是否相等的实例代码,希望对大家有所帮助