python实现一组典型数据格式转换

本文实例为大家分享了一组典型数据格式转换的python实现代码，供大家参考，具体内容如下

有一组源数据，第一行会是个日期数据，第二行标明字段，再接下来是两行数据行。

1018 14:31:30.193
type succ fail
sour_sm 1308 1205
data_sm 2205 3301
1019 16:32:30.201
type succ fail
data_sm 3308 2206
data_sm 1765 1105
1020 18:00:00.203
type succ fail
sour_sm 7804 1105
data_sm 2976 1300

要转换成数据

time               type    succ fail  total
1018 14:31:30.193  sour_sm 1308 1205  2513
1018 14:31:30.193  data_sm 2205 3301  5506
1019 16:32:30.201  data_sm 3308 2206  5514
1019 16:32:30.201  data_sm 1765 1105  2870
1020 18:00:00.203  sour_sm 7804 1105  8909
1020 18:00:00.203  data_sm 2976 1300  4276

这个时候可以使用python来处理，代码如下:

# coding = utf-8
fd = open(r"output.txt", "w", encoding="utf-8")
fd.write("%s\t\t\t\t%s\t%s\t%s\t%s\n" % ("time", "type", "succ", "fail", "total"))
 
with open(r"data.txt", "r", encoding="utf-8") as fd1:
 lines = fd1.readlines()
 time1 = lines[0::4]
 data1 = lines[2::4]
 data2 = lines[3::4]
 for (i, line) in enumerate(time1):
 time = line.strip()
 type_1 = data1[i].strip().split()[0]
 succ_1 = data1[i].strip().split()[1]
 fail_1 = data1[i].strip().split()[2]
 total_1 = str(int(succ_1) + int(fail_1))
 type_2 = data2[i].strip().split()[0]
 succ_2 = data2[i].strip().split()[1]
 fail_2 = data2[i].strip().split()[2]
 total_2 = str(int(succ_2) + int(fail_2))
 fd.write("%s\t%s\t%s\t%s\t%s\n" % (time, type_1, succ_1, fail_1, total_1))
 fd.write("%s\t%s\t%s\t%s\t%s\n" % (time, type_2, succ_2, fail_2, total_2))
fd.close()

生成文件格式如下，基本上满足了需求。

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