mysql主从数据库状态检测功能使用php如何实现？

这篇文章主要介绍了PHP实现的mysql主从数据库状态检测功能,结合具体实例形式分析了php检测多个mysql主从数据库连接状态的相关实现技巧,需要的朋友可以参考下

本文实例讲述了PHP实现的mysql主从数据库状态检测功能。分享给大家供大家参考，具体如下：

实例：

<?php
/**
 * 检测多个主从数据库是否挂掉
 * 建立从数据库$slave_db的二维数组，内容包含每个从服务器的配置数据
 */
header("Content-Type: text/html; charset=utf-8");
set_time_limit(0);
$slave_db = array(
  'db1'=>array(
    'hostname' => '127.0.0.1',
    'port' => 3306,
    'database' => 'test',
    'username' => 'root',
    'password' => '111111',
    'charset' => 'utf8',
  ),
  'db2'=>array(
    'hostname' => '127.0.0.2',
    'port' => 3306,
    'database' => 'test',
    'username' => 'root',
    'password' => '111111',
    'charset' => 'utf8',
  ),
);
$content = '';
foreach ($slave_db as $db_key) {
  $host = $db_key['hostname'];
  $port = $db_key['port'];
  $db_user = $db_key['username'];
  $db_pass = $db_key['password'];
  $slave_link = mysql_connect($host,$db_user,$db_pass);
  if(mysql_errno()) {
    $content .= "从数据库( $host )无法连接 ！ <br/>";
    $content .= mysql_error() . "<br/>";
    continue;
  }
  $sql = "show slave status";
  $result = mysql_query($sql, $slave_link);
  $row = mysql_fetch_assoc($result);
  $Slave_IO_Running = $row['Slave_IO_Running'];
  $Slave_SQL_Running = $row['Slave_SQL_Running'];
  if ('Yes' == $Slave_IO_Running && 'Yes' == $Slave_SQL_Running) {
  } else {
    $content .= "从数据库( $host )挂掉了！ <br/>";
  }
  mysql_free_result($result);
  mysql_close($slave_link);
}
//若报错信息不为空，发送报错邮件
if(!empty($content)) {
  $title = '主从数据库状态检测报错 ';
  $content = date("Y-m-d H:i:s",time()) . "<br/>" . $content;
  $sendurl = "http://localhost/api.ftrend.com/test.php?title=".$title."&content=".$content;
  $result = file_get_contents($sendurl);
  if('ok' != $result) {
    $message = date("Y-m-d H:i:s",time()).'slaveStatus.php主从数据库状态检测报错,邮件发送失败!'."\n";
    $content = str_replace("<br/>", "\n", $content);
    $message .= $content;
    error_log($message,3,"error.log");
  }
}

<?php
$title = $_GET['title'];
$content = $_GET['content'];
$content = str_replace("<br/>", "\n", $content);
error_log($title."\n",3,'error.log');
error_log($content."\n",3,'error.log');
echo 'ok';

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