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Codeforces Round #277.5 (Div. 2)C??Given Length and Sum of Digits._html/css_WEB-ITnose

程序员文章站 2022-06-08 16:41:12
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C. Given Length and Sum of Digits...

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) ? the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers ? first the minimum possible number, then ? the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Sample test(s)

Input

2 15

Output

69 96

Input

3 0

Output

-1 -1

贪心,考虑最大的时候把数组赋值为9,考虑最小的时候把数组第一位赋值1,其他为赋值0


#include #include #include #include #include #include #include #include #include #include #include using namespace std;int s1[110], s2[110];int main(){	int m, s;	while (~scanf("%d%d", &m, &s))	{		if (s == 0 && m == 1)		{			printf("0 0\n");			continue;		}		if (m * 9 = dis)			{				s1[cnt] += dis;				break;			}			dis -= (9 - s1[cnt]);			s1[cnt] = 9;			cnt--;		}		for (int i = 1; i = dis)			{				s2[cnt] -= dis;				break;			}			dis -= (s2[cnt]);			s2[cnt] = 0;			cnt--;		}		for (int i = 1; i