fgetcsv函数读取csv文件中文字符串的问题

读取csv文件数据函数：

2. function getData($file) {
3. $arr = array();
4. if(($handle = fopen($file,"r")) !== FALSE) {
5. while(($data = fgetcsv($handle)) !== FALSE) {
7. $tmp = array();
8. foreach($data as $key=>$v) {
9. $tmp[] = mb_convert_encoding($v,"UTF-8","gbk"); /*要将gbk码转为utf-8，否则会出现乱码*/
10. }
12. $arr[] = $tmp;
13. }
14. }
16. return $arr;
17. }

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发现读取的中文字符串为空....

解决方法：将fgetcsv函数换成自定义的_fgetcsv函数

2. function _fgetcsv(&$handle, $length = null, $d = ',', $e = '"') {
3. $d = preg_quote($d);
4. $e = preg_quote($e);
5. $_line = "";
6. $eof=false;
7. while ($eof != true) {
8. $_line .= (empty ($length) ? fgets($handle) : fgets($handle, $length));
9. $itemcnt = preg_match_all('/' . $e . '/', $_line, $dummy);
10. if ($itemcnt % 2 == 0)
11. $eof = true;
12. }
13. $_csv_line = preg_replace('/(?: |[ ])?$/', $d, trim($_line));
14. $_csv_pattern = '/(' . $e . '[^' . $e . ']*(?:' . $e . $e . '[^' . $e . ']*)*' . $e . '|[^' . $d . ']*)' . $d . '/';
15. preg_match_all($_csv_pattern, $_csv_line, $_csv_matches);
16. $_csv_data = $_csv_matches[1];
17. for ($_csv_i = 0; $_csv_i $_csv_data[$_csv_i] = preg_replace('/^' . $e . '(.*)' . $e . '$/s', '$1' , $_csv_data[$_csv_i]);
18. $_csv_data[$_csv_i] = str_replace($e . $e, $e, $_csv_data[$_csv_i]);
19. }
20. return empty ($_line) ? false : $_csv_data;
21. }

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