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Fight Against Monsteres_贪心

程序员文章站 2022-06-06 17:50:04
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Fight Against Monsteres_贪心

Fight Against Monsteres_贪心

本题按照性价比排序依次打怪兽;

每只怪兽的攻击力/打每只怪兽的次数   排序

#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5+5;
typedef long long ll;
int n,m;
struct node
{
	ll hp,at;
	double bi;
}spe[maxn];
ll judge(ll a)
{
	for(ll i = 1; i <= a; i++ )
		if((i*(i+1)/2) >=a)
			return i;
}
int cmp(node a,node b)
{
	return a.bi>b.bi;
}
int main()
{
	int ant = 1;
	scanf("%d",&n);
	while(n--)
	{
		scanf("%d",&m);
		for(int i = 0; i < m; i++)
		{
			scanf("%lld%lld",&spe[i].hp,&spe[i].at);
			spe[i].hp = judge(spe[i].hp);
			spe[i].bi =((double)spe[i].at/(double)spe[i].hp);
		}
		sort(spe,spe+m,cmp);
		ll sum = 0,cnt = 0;
		for(int i = 0; i < m; i++)
		{
			sum += (spe[i].hp+cnt)*spe[i].at;
			cnt += spe[i].hp;
		}
		printf("Case #%d: %lld\n",ant++,sum);
	}
	return 0;
}