关于java中nextline读取空白行的问题
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2022-06-04 19:29:12
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最近在做java作业, 发现了一个问题, 就是nextline其实会接收缓冲区的\r, 使得在程序运行时nextline像是跳过了一样, 其实不然, 它只是读取了上一个enter时的\r, 如我的如下功能代码
public void run() {
Scanner scan = new Scanner(System.in);
int ord, book_order;
int flag = 0;
String isbn = new String();
String nme = new String();
while (flag == 0) {
System.out.println("Function List:");
System.out.println("1.Show the book list");
System.out.println("2.Find book");
System.out.println("3.Add book");
System.out.println("4.Delete book");
System.out.println("0.Exit");
System.out.println("Please input the functon order:");
ord = scan.nextInt();
switch (ord) {
case 0: {
flag = 1;
break;
}
case 1: {
Print();
break;
}
case 2: {
Scanner in = new Scanner(System.in);
System.out.println("Please input the ISBN of book you want to find:");
isbn = in.nextLine();
book_order = Find(isbn);
if (book_order != 0) {
System.out.println("Success!");
System.out.println("Name:" + books[book_order].name);
System.out.println("ISBN:" + books[book_order].ISBN);
System.out.println();
} else {
System.out.println("Error!No such book!");
System.out.println();
}
break;
}
case 3: {
Scanner in = new Scanner(System.in);
System.out.println("Please input the name of the book:");
nme = scan.nextLine();
System.out.println("Please input the ISBN of the book:");
isbn = scan.nextLine();
if (Add(nme, isbn)) {
System.out.println("Add successfully!");
System.out.println();
} else {
System.out.println("Failed to add!It's out of range!");
System.out.println();
}
break;
}
case 4: {
System.out.println("Please input the ISBN of book you want to delete:");
isbn = scan.nextLine();
if (Del(isbn)) {
System.out.println("Delete successfully!");
System.out.println();
} else {
System.out.println("Failed to delete!No such book!");
System.out.println();
}
break;
}
}
}
scan.close();
}
}
在这里, 我一开始就已经实例化了一个scanner对象, 命名为scan, 然后在输入功能选项时我们调用了nextInt, 那么在输入完之后, 整数被读取进去了, 但是那个\r还留在scan的buffer区域, 所以, 如果我们添加书籍的话, 再次使用scan的nextline来读取书名的话, nextline就会得到scan的buffer区域中的\r,导致程序错误, 所以,在这里看到老师的代码之后, 得到启发, 重新新建一个scanner对象, 在这里可以使用in
public void run() {
Scanner scan = new Scanner(System.in);
int ord, book_order;
int flag = 0;
String isbn = new String();
String nme = new String();
while (flag == 0) {
System.out.println("Function List:");
System.out.println("1.Show the book list");
System.out.println("2.Find book");
System.out.println("3.Add book");
System.out.println("4.Delete book");
System.out.println("0.Exit");
System.out.println("Please input the functon order:");
ord = scan.nextInt();
switch (ord) {
case 0: {
flag = 1;
break;
}
case 1: {
Print();
break;
}
case 2: {
Scanner in = new Scanner(System.in);
System.out.println("Please input the ISBN of book you want to find:");
isbn = in.nextLine();
book_order = Find(isbn);
if (book_order != 0) {
System.out.println("Success!");
System.out.println("Name:" + books[book_order].name);
System.out.println("ISBN:" + books[book_order].ISBN);
System.out.println();
} else {
System.out.println("Error!No such book!");
System.out.println();
}
break;
}
case 3: {
Scanner in = new Scanner(System.in);
System.out.println("Please input the name of the book:");
nme = in.nextLine();
System.out.println("Please input the ISBN of the book:");
isbn = in.nextLine();
if (Add(nme, isbn)) {
System.out.println("Add successfully!");
System.out.println();
} else {
System.out.println("Failed to add!It's out of range!");
System.out.println();
}
break;
}
case 4: {
System.out.println("Please input the ISBN of book you want to delete:");
isbn = scan.nextLine();
if (Del(isbn)) {
System.out.println("Delete successfully!");
System.out.println();
} else {
System.out.println("Failed to delete!No such book!");
System.out.println();
}
break;
}
}
}
scan.close();
}
}
运行结果如下:
此外, 也可以和cpp一样, 使用一次scan.nextLine将那个\r读取.
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