linux c pcre 正则匹配多个目标

#include <pcre.h>

#define OVECCOUNT 30

void main() {
    char *in = "20171208121020Z   20171208121020Z\n20171208121020Z";
    char *pattern = "(19|20)([\\d]{2})([0-1][0-9])([0-3][0-9])([0-2][0-9])([0-6][0-9])([0-6][0-9])(\\.?[0-9]{0,3})(Z?)";
    pcre *re;
    const char *err, *p;
    int erroffset;
    int ovector[OVECCOUNT], i, rc, srcLen, ret;
    char *src, *src1;
    re = pcre_compile(pattern, 0, &err, &erroffset, NULL);
    if (NULL == re) {
        printf("pcre compile error:%s", err);
        return;
    }
    //try multiple target match
    src = src1 = in;
    srcLen = strlen(src);
    while (1) {
        printf("<%s>\n", src);
        rc = pcre_exec(re, NULL, src, srcLen, 0, 0, ovector, OVECCOUNT);
        if (rc < 0) {
            printf("pcre exec error");
            break;
        }
        for (i = 0; i < rc; i++) {
            int ret = pcre_get_substring(src, ovector, rc, i, &p);
            printf("%d, %s\n", ret, p);
            pcre_free_substring(p);
        }
        ret = pcre_get_substring(src, ovector, rc, 0, &p);
        pcre_free_substring(p);
        if (ret > 0) {
            src1 += ret + ovector[0];
            srcLen = srcLen - (src1 - src);
            src = src1;
            if (srcLen <= 0) {
                break;
            }
        }
    }
    pcre_free(re);


}