like 查询，报错，求指点

      mysql_connect("localhost", "root", "123") or die("Could not connect: " . mysql_error());	 mysql_select_db("iweibo");    $result = mysql_query("SELECT * FROM user where username like %admin%");    while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {			var_dump($row);    }

报错信息：

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\34\test.php on line 19

回复讨论(解决方案)

$result = mysql_query("SELECT * FROM user where username like '%admin%'");

肯定是SQL语句的问题，echo 你的sql语句，拿到数据库去运行就知道什么原因了。
$result = mysql_query("SELECT * FROM user where username like '%admin%'");
试一试。