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二分查找LeetCode 744 Find Smallest Letter Greater Than Target

程序员文章站 2022-06-03 14:05:52
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LeetCode 744

Find Smallest Letter Greater Than Target

  • Problem Description:
    返回比目标字母大且序号最小的字母。
    具体的题目信息:
    https://leetcode.com/problems/find-smallest-letter-greater-than-target/description/
  • Example:
    二分查找LeetCode 744 Find Smallest Letter Greater Than Target
  • Solution:
    • 解题思路:题目给出的样例中存在重复字母,我们通过排序和插入得到一个从小到大排列且不重复的字母序列,然后通过二分查找确定是否能找到目标字母,如果可以找到,则返回该目标字母的下一位;如果找不到,则返回low指向的字母。
    • 编程实现:
class Solution {
public:
    char nextGreatestLetter(vector<char>& letters, char target) {
        sort(letters.begin(), letters.end());
        vector<char> arr;
        arr.push_back(letters[0]);
        char temp = letters[0];
        for (int i = 1; i < letters.size(); i++) {
            if(letters[i] != temp) {
                arr.push_back(letters[i]);
                temp = letters[i];
            }
        }
        int low = 0, high = arr.size()-1, mid, flag = 0, res;
        while(low<=high) {
            mid = low+(high-low)/2;
            if (arr[mid] == target) {
                flag = 1;
                break;
            } else if (arr[mid]>target) {
                high = mid-1;
            } else {
                low = mid+1;
            }
        }
        if (flag == 1)
            res = (mid+1)%arr.size();
        else
            res = low%arr.size();
        return arr[res];
    }
};
相关标签: binary_search