jpgraph路径问题.

include ("src/jpgraph.php")里所说的jpgraph.php文件放在C:\Jpgraph\src\jpgraph里.
运行时显示错误：
Warning: include(src/jpgraph.php): failed to open stream: No such file or directory in C:\Program Files (x86)\EasyPHP-12.1\www\formulaire\reponse_formulaire_systemB_1.php on line 30

Warning: include(): Failed opening 'src/jpgraph.php' for inclusion (include_path='.;C:\php\pear') in C:\Program Files (x86)\EasyPHP-12.1\www\formulaire\reponse_formulaire_systemB_1.php on line 30

Warning: include(src/jpgraph_bar.php): failed to open stream: No such file or directory in C:\Program Files (x86)\EasyPHP-12.1\www\formulaire\reponse_formulaire_systemB_1.php on line 31

Warning: include(): Failed opening 'src/jpgraph_bar.php' for inclusion (include_path='.;C:\php\pear') in C:\Program Files (x86)\EasyPHP-12.1\www\formulaire\reponse_formulaire_systemB_1.php on line 31

Fatal error: Class 'Graph' not found in C:\Program Files (x86)\EasyPHP-12.1\www\formulaire\reponse_formulaire_systemB_1.php on line 33
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找了不少材料说要在php.ini里改，但是怎么改都是出错，请问这里到底怎么写呢？
;;;;;;;;;;;;;;;;;;;;;;;;;
; Paths and Directories ;
;;;;;;;;;;;;;;;;;;;;;;;;;
; Windows: "\path1;\path2"
;include_path = ".;${path}\php\includes"

多谢各位大神的指点.

回复讨论(解决方案)

如果
include ("src/jpgraph.php");
那么 jpgraph.php 应在当前目录的 src 子目录中

如果
include ("src/jpgraph.php");
那么 jpgraph.php 应在当前目录的 src 子目录中

谢谢你的回答啊，我想问的是php.ini里如何改啊？
;;;;;;;;;;;;;;;;;;;;;;;;;
; Paths and Directories ;
;;;;;;;;;;;;;;;;;;;;;;;;;
; Windows: "\path1;\path2"
;include_path = ".;${path}\php\includes"

这里要如何写？