一个初始值为0的变量,两个线程对其交替操作,一个加1一个减1,来5轮
程序员文章站
2022-03-09 19:01:32
...
题目:一个初始值为0的变量,两个线程对其交替操作,一个加1一个减1,来5轮
class ShareData{
private int number=0;
private Lock lock=new ReentrantLock();
/**
* 1.一个Condition的实例必须与一个Lock绑定,Condition一般都是作为Lock的内部实现
* 2.Condition与Lock配合可以实现等待/通知模式
* 3.Condition接口也提供了类似Object的监视器方法
*/
private Condition condition=lock.newCondition();
public void increment() throws Exception{
lock.lock();
try {
//1.判断
while (number!=0){
//等待,不能生产
condition.await();
}
//2.干活
number++;
System.out.println(Thread.currentThread().getName()+"\t"+number);
//3.通知唤醒
condition.signalAll();
}catch (Exception e){
e.printStackTrace();
}finally {
lock.unlock();
}
}
public void decrement() throws Exception{
lock.lock();
try {
//1.必须要用while判断,防止虚假唤醒
while (number==0){
//等待,不能消费
condition.await();
}
//2.干活
number--;
System.out.println(Thread.currentThread().getName()+"\t"+number);
//3.通知唤醒
condition.signalAll();
}catch (Exception e){
e.printStackTrace();
}finally {
lock.unlock();
}
}
}
public class ProductConsumer_Traditional {
public static void main(String[] args) {
ShareData shareData=new ShareData();
new Thread(()->{
for (int i = 1; i <=5; i++) {
try {
shareData.increment();
} catch (Exception e) {
e.printStackTrace();
}
}
},"AA").start();
new Thread(()->{
for (int i = 1; i <=5; i++) {
try {
shareData.decrement();
} catch (Exception e) {
e.printStackTrace();
}
}
},"BB").start();
}
}
虚假唤醒?
源码:
As in the one argument version, interrupts and spurious wakeups are possible, and this method should always be used in a loop:
synchronized (obj) {
while (<condition does not hold>)
obj.wait();
... // Perform action appropriate to condition
}
将上述代码中的线程数量再增加两个,将await放入if条件判断中,就会出现虚假唤醒,导致出错
上一篇: ES6的解构赋值实例详解
下一篇: vue无痕刷新的实现方法介绍