Linux shell脚本实现CPU预警
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2022-06-02 08:42:40
如果cpu占用率持续达到80以上则调用打印java线程占用率堆栈的脚本,见,具体用法见他的github wiki!
#!/bin/bash
#cpu idle...
如果cpu占用率持续达到80以上则调用打印java线程占用率堆栈的脚本,见,具体用法见他的github wiki!
#!/bin/bash #cpu idle percent cpu_idle=`top -b -d 1 -n 2 | grep cpu | awk 'nr>1{print $5}' | cut -f 1 -d "."` if [ -d "/opt/scripts/log" ] then cd /opt/scripts else mkdir /opt/scripts/log fi count=0 condition=true while condition do if [ $cpu_idle -le 20 ] then pids=`top -b -d 1 -n 1 | grep java | awk '{if($9 > 80) print $1}'` for ((a = 1; a < 10; a++)) do for pid in $pids doi #involve jdk existence check later date=`date +%y%m%d%h%m` sh showstack.sh -c 30 -p $pid > log/stack_$pid_$date.log jstat -gcutil $pid > log/gc_$pid_$date.log done done for pid in $pids do date=`date +%y%m%d%h%m` jmap -heap $pid > log/heap_$pid_$date.log done count++ cpu_idle=`top -b -d 1 -n 2 | grep cpu | awk 'nr>1{print $5}' | cut -f 1 -d "."` if [ $count -ge 3] then #send emaili #server ip address ip=`ifconfig eth0 | grep "inet addr" | cut -f 2 -d ":" | cut -f 1 -d " "` condition=false count=0 fi else condition=false count=0 fi done
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