MySQL实现Oracle或者PostgreSQL的row_numberover这样的排名语法_MySQL

bitsCN.com PostgreSQL 和Oracle 都提供了 row_number() over() 这样的语句来进行对应的字段排名， 很是方便。 MySQL却没有提供这样的语法。
Table "ytt.t1" Column | Type | Modifiers --------+-----------------------+----------- i_name | character varying(10) | not null rank | integer | not null

t_girl=# select * from t1 order by i_name; i_name | rank ---------+------ Charlie | 12 Charlie | 12 Charlie | 13 Charlie | 10 Charlie | 11 Lily | 6 Lily | 7 Lily | 7 Lily | 6 Lily | 5 Lily | 7 Lily | 4 Lucy | 1 Lucy | 2 Lucy | 2 Ytt | 14 Ytt | 15 Ytt | 14 Ytt | 14 Ytt | 15 (20 rows)

t_girl=# select i_name,rank, row_number() over(partition by i_name order by rank desc) as rank_number from t1; i_name | rank | rank_number ---------+------+------------- Charlie | 13 | 1 Charlie | 12 | 2 Charlie | 12 | 3 Charlie | 11 | 4 Charlie | 10 | 5 Lily | 7 | 1 Lily | 7 | 2 Lily | 7 | 3 Lily | 6 | 4 Lily | 6 | 5 Lily | 5 | 6 Lily | 4 | 7 Lucy | 2 | 1 Lucy | 2 | 2 Lucy | 1 | 3 Ytt | 15 | 1 Ytt | 15 | 2 Ytt | 14 | 3 Ytt | 14 | 4 Ytt | 14 | 5 (20 rows)

t_girl=# select i_name,rank, row_number() over(partition by i_name ) as rank_number from t1; i_name  | rank | rank_number ---------+------+------------- Charlie	 |   12 |           1 Charlie	|   12 |           2 Charlie	|   13 |           3 Charlie	|   10 |           4 Charlie	|   11 |           5 Lily		|    6 |           1 Lily		|    7 |           2 Lily		|    7 |           3 Lily		|    6 |           4 Lily		|    5 |           5 Lily		|    7 |           6 Lily		|    4 |           7 Lucy	|    1 |           1 Lucy	|    2 |           2 Lucy	|    2 |           3 Ytt		|   14 |           1 Ytt		|   15 |           2 Ytt		|   14 |           3 Ytt		|   14 |           4 Ytt		|   15 |           5(20 rows)

t_girl=# select i_name,rank, row_number() over() as rank_number from t1; i_name  | rank | rank_number ---------+------+------------- Lily		 |    7 |           1 Lucy	|    2 |           2 Ytt		|   14 |           3 Ytt		|   14 |           4 Charlie	|   12 |           5 Charlie	|   13 |           6 Lily		|    7 |           7 Lily		|    4 |           8 Ytt		|   14 |           9 Lily		|    6 |          10 Lucy	|    1 |          11 Lily		|    7 |          12 Ytt		|   15 |          13 Lily		|    6 |          14 Charlie	|   11 |          15 Charlie	|   12 |          16 Lucy	|    2 |          17 Charlie	|   10 |          18 Lily		|    5 |          19 Ytt		|   15 |          20(20 rows)

DELIMITER $$ USE `t_girl`$$ DROP PROCEDURE IF EXISTS `sp_rownumber`$$ CREATE PROCEDURE `sp_rownumber`( IN f_table_name VARCHAR(64), IN f_column_partitionby VARCHAR(64), IN f_column_orderby VARCHAR(64), IN f_is_asc CHAR(4) ) BEGIN -- Created by ytt at 2014/1/10 -- Do a row_number() over() DECLARE i INT; -- Create a temporary table to save result. DROP TABLE IF EXISTS tmp_rownum; SET @stmt = CONCAT('create temporary table tmp_rownum select *,''rownum'' from ',f_table_name,' where 1 = 0'); PREPARE s1 FROM @stmt; EXECUTE s1; SET i = 0; SET @j = 0; SET @v_column_paritionby = ''; -- Check whether parition column is null or not. IF (f_column_partitionby = '' OR f_column_partitionby IS NULL) THEN -- No additional parition column. SET @stmt = CONCAT('insert into tmp_rownum select *,@j:= @j+1 as rownum from ', f_table_name); PREPARE s1 FROM @stmt; EXECUTE s1; ELSE -- Give partition column. SET @stmt = CONCAT('select count(*) from (select count(*) from ',f_table_name,' group by ', f_column_partitionby,') as a into @cnt'); PREPARE s1 FROM @stmt; EXECUTE s1; WHILE i

CALL sp_rownumber('t1','i_name','rank','desc');query resulti_name	rank	rownumCharlie	13	1Charlie	12	2Charlie	12	3Charlie	11	4Charlie	10	5Lily		7	1Lily		7	2Lily		7	3Lily		6	4Lily		6	5Lily		5	6Lily		4	7Lucy	2	1Lucy	2	2Lucy	1	3Ytt		15	1Ytt		15	2Ytt		14	3Ytt		14	4Ytt		14	5

第二种，

CALL sp_rownumber('t1','i_name',NULL,NULL);query resulti_name	rank	rownumCharlie	12	1Charlie	13	2Charlie	11	3Charlie	12	4Charlie	10	5Lily		7	1Lily		7	2Lily		4	3Lily		6	4Lily		7	5Lily		6	6Lily		5	7Lucy	2	1Lucy	1	2Lucy	2	3Ytt		14	1Ytt		14	2Ytt		14	3Ytt		15	4Ytt		15	5

第三种，

CALL sp_rownumber('t1',NULL,NULL,NULL);query resulti_name	rank	rownumLily		7	1Lucy	2	2Ytt		14	3Ytt		14	4Charlie	12	5Charlie	13	6Lily		7	7Lily		4	8Ytt		14	9Lily		6	10Lucy	1	11Lily		7	12Ytt		15	13Lily		6	14Charlie	11	15Charlie	12	16Lucy	2	17Charlie	10	18Lily		5	19Ytt		15	20

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