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ValueError: invalid literal for int() with base 10: '7.8000000e+02'

程序员文章站 2022-06-01 22:09:27
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ValueError: invalid literal for int() with base 10: '7.8000000e+02'

1. ValueError 1

number_string = "7.8000000e+02"

number_value = int(number_string)

==>

/usr/bin/python2.7 /home/strong/PycharmProjects/crash_course/python_function/number_string.py
Traceback (most recent call last):
  File "/home/strong/PycharmProjects/crash_course/python_function/number_string.py", line 4, in <module>
    number_value = int(number_string)
ValueError: invalid literal for int() with base 10: '7.8000000e+02'

Process finished with exit code 1

Python int( ) 函数的输入字符串中可以包含数字字符和 + 、-符号,不能包含其它非数字字符。


2. example 1

number_string = "7.8000000e+02"

float_value = float(number_string)

int_value1 = int(float_value)
int_value2 = int(float(number_string))

print("float_value: " + str(float_value))
print("int_value1: " + str(int_value1))
print("int_value2: " + str(int_value2))

==>

/usr/bin/python2.7 /home/strong/PycharmProjects/crash_course/python_function/number_string.py
float_value: 780.0
int_value1: 780
int_value2: 780

Process finished with exit code 0

3. example 2

number_string1 = "+99"
number_string2 = "-99"

int_value1 = int(number_string1)
int_value2 = int(number_string2)

print("int_value1: " + str(int_value1))
print("int_value2: " + str(int_value2))

==>


/usr/bin/python2.7 /home/strong/PycharmProjects/crash_course/python_function/number_string.py
int_value1: 99
int_value2: -99

Process finished with exit code 0







相关标签: int