用c++实现AES基本算法

用c++实现AES基本算法

#include

#include

#include

using namespace std;

typedef bitset<8> byte;

typedef bitset<32> word;

typedef bitset<128> fword;

//测试密钥：00012001710198aeda79171460153594

//测试明文：0001000101a198afda78173486153566

//结果密文：6cdd596b8f5642cbd23b47981a65422a

byte S_Box[16][16] = {

{0x63, 0x7C, 0x77, 0x7B, 0xF2, 0x6B, 0x6F, 0xC5, 0x30, 0x01, 0x67, 0x2B, 0xFE, 0xD7, 0xAB, 0x76},

{0xCA, 0x82, 0xC9, 0x7D, 0xFA, 0x59, 0x47, 0xF0, 0xAD, 0xD4, 0xA2, 0xAF, 0x9C, 0xA4, 0x72, 0xC0},

{0xB7, 0xFD, 0x93, 0x26, 0x36, 0x3F, 0xF7, 0xCC, 0x34, 0xA5, 0xE5, 0xF1, 0x71, 0xD8, 0x31, 0x15},

{0x04, 0xC7, 0x23, 0xC3, 0x18, 0x96, 0x05, 0x9A, 0x07, 0x12, 0x80, 0xE2, 0xEB, 0x27, 0xB2, 0x75},

{0x09, 0x83, 0x2C, 0x1A, 0x1B, 0x6E, 0x5A, 0xA0, 0x52, 0x3B, 0xD6, 0xB3, 0x29, 0xE3, 0x2F, 0x84},

{0x53, 0xD1, 0x00, 0xED, 0x20, 0xFC, 0xB1, 0x5B, 0x6A, 0xCB, 0xBE, 0x39, 0x4A, 0x4C, 0x58, 0xCF},

{0xD0, 0xEF, 0xAA, 0xFB, 0x43, 0x4D, 0x33, 0x85, 0x45, 0xF9, 0x02, 0x7F, 0x50, 0x3C, 0x9F, 0xA8},

{0x51, 0xA3, 0x40, 0x8F, 0x92, 0x9D, 0x38, 0xF5, 0xBC, 0xB6, 0xDA, 0x21, 0x10, 0xFF, 0xF3, 0xD2},

{0xCD, 0x0C, 0x13, 0xEC, 0x5F, 0x97, 0x44, 0x17, 0xC4, 0xA7, 0x7E, 0x3D, 0x64, 0x5D, 0x19, 0x73},

{0x60, 0x81, 0x4F, 0xDC, 0x22, 0x2A, 0x90, 0x88, 0x46, 0xEE, 0xB8, 0x14, 0xDE, 0x5E, 0x0B, 0xDB},

{0xE0, 0x32, 0x3A, 0x0A, 0x49, 0x06, 0x24, 0x5C, 0xC2, 0xD3, 0xAC, 0x62, 0x91, 0x95, 0xE4, 0x79},

{0xE7, 0xC8, 0x37, 0x6D, 0x8D, 0xD5, 0x4E, 0xA9, 0x6C, 0x56, 0xF4, 0xEA, 0x65, 0x7A, 0xAE, 0x08},

{0xBA, 0x78, 0x25, 0x2E, 0x1C, 0xA6, 0xB4, 0xC6, 0xE8, 0xDD, 0x74, 0x1F, 0x4B, 0xBD, 0x8B, 0x8A},

{0x70, 0x3E, 0xB5, 0x66, 0x48, 0x03, 0xF6, 0x0E, 0x61, 0x35, 0x57, 0xB9, 0x86, 0xC1, 0x1D, 0x9E},

{0xE1, 0xF8, 0x98, 0x11, 0x69, 0xD9, 0x8E, 0x94, 0x9B, 0x1E, 0x87, 0xE9, 0xCE, 0x55, 0x28, 0xDF},

{0x8C, 0xA1, 0x89, 0x0D, 0xBF, 0xE6, 0x42, 0x68, 0x41, 0x99, 0x2D, 0x0F, 0xB0, 0x54, 0xBB, 0x16}

};

void ox_to_b(string &ppx,string &ppz) //16进制字符串转换2进制函数

{

string ppl[32];

for(int cv = 0;cv<32;cv++)

{

switch(ppx[cv]){

case '0': ppl[cv] = "0000";break;

case '1': ppl[cv] = "0001";break;

case '2': ppl[cv] = "0010";break;

case '3': ppl[cv] = "0011";break;

case '4': ppl[cv] = "0100";break;

case '5': ppl[cv] = "0101";break;

case '6': ppl[cv] = "0110";break;

case '7': ppl[cv] = "0111";break;

case '8': ppl[cv] = "1000";break;

case '9': ppl[cv] = "1001";break;

case 'A': ppl[cv] = "1010";break;

case 'a': ppl[cv] = "1010";break;

case 'B': ppl[cv] = "1011";break;

case 'b': ppl[cv] = "1011";break;

case 'C': ppl[cv] = "1100";break;

case 'c': ppl[cv] = "1100";break;

case 'D': ppl[cv] = "1101";break;

case 'd': ppl[cv] = "1101";break;

case 'E': ppl[cv] = "1110";break;

case 'e': ppl[cv] = "1110";break;

case 'F': ppl[cv] = "1111";break;

default: ppl[cv] = "1111";break;//待解决：ppz+-ppl[cv]不行，或许可以调用某个string函数

}

}

ppz = ppl[0] +ppl[1]+ppl[2]+ppl[3]+ppl[4]+ppl[5]+ppl[6]+ppl[7]+ppl[8]+ppl[9]+ppl[10]+ppl[11]+ppl[12]+ppl[13]+ppl[14]+ppl[15]+ppl[16]+ppl[17]+ppl[18]+ppl[19]+ppl[20]+ppl[21]+ppl[22]+ppl[23]+ppl[24]+ppl[25]+ppl[26]+ppl[27]+ppl[28]+ppl[29]+ppl[30]+ppl[31];

}

void PutOutState(word so[4])//输出状态

{

for(int jl = 0;jl<4;jl++)

cout< cout<

}

void circle(fword &s,word &v)

{

for(int t = 0;t<32;t++)

v[t] = s[t];

}

void fword_to_word(fword &x,word y[4])//四字转化为单字

{

fword temp;

for(int o = 0;o<4;o++)

{

temp=x>>o*32;

circle(temp,y[3-o]); //注意是反着放的

}

}

word Rotl(word &v,int gh)//左移函数

{

word stemp;

word ktemp;

stemp = v>>24-gh*8;

ktemp = v<<8+gh*8;

return stemp|ktemp;

}

word Rcon[10] = {0x01000000, 0x02000000, 0x04000000, 0x08000000, 0x10000000,

0x20000000, 0x40000000, 0x80000000, 0x1b000000, 0x36000000}; //轮常数

word byte_to_word(byte r[],int j)//状态列字节转换为字的函数

{

word n(r[0+4*j].to_string()+r[1+4*j].to_string()+r[2+4*j].to_string()+r[3+4*j].to_string());

//cout< return n;

}

word Byte_to_word(byte r[],int gg)//状态行字节转化为字的函数

{

word n(r[0+gg].to_string()+r[4+gg].to_string()+r[8+gg].to_string()+r[12+gg].to_string());

//cout< return n;

}

word SubByte(word &vv)//S盒变换

{

byte p[4];

// cout< // cout< for(int u = 0;u<4;u++)

{

int col = vv[u*8]+vv[u*8+1]*2+vv[u*8+2]*4+vv[u*8+3]*8; //注意二进制站位和string不同

int row = vv[u*8+4]+vv[u*8+5]*2+vv[u*8+6]*4+vv[u*8+7]*8;

// cout<